이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "prize.h"
#include <bits/stdc++.h>
using namespace std;
#define pii pair<int, int>
#define mp make_pair
#define maxn 200010
int blk;
int qs[maxn][2];
int numqueries = 0;
pii query(int spot) {
if (qs[spot][0] != -1)
return pii(qs[spot][0], qs[spot][1]);
numqueries++;
assert(numqueries <= 10000); //induce run time error instead of WA
//seems that above got hit
vector<int> res = ask(spot);
qs[spot][0] = res[0];
qs[spot][1] = res[1];
return pii(res[0], res[1]);
}
queue<pair<pii, pii>> q;
int find_best(int n) {
//we don't really care what happens for smaller n,
// b/c it is not a function of n
for (int i = 0; i < n; i++) {
qs[i][0] = qs[i][1] = -1;
}
//i am a little worried about exact blk bound
blk = sqrt(n)+50; //changed from 5 to 50
blk = min(blk, n); //just making sure
int mxind = -1;
int mxstuff = -1;
for(int i = 0; i < blk; i++) {
pii res = query(i);
if(res.first + res.second == 0)
return i; //this will always be there
if (res.first+ res.second >= mxstuff) {
mxstuff = res.first + res.second;
mxind = i;
}
}
int aft = query(mxind).second;
int numtot = mxstuff; //total number less than biggest guy
int nc = 0;
for (int i = 0; i < blk; i++) {
pii cur = query(i);
if (cur.first + cur.second != numtot) nc++;
}
q.push(mp(mp(blk, n-1), mp(nc, 0)));
//gives number to left & right of range
while (q.size()) {
auto cur = q.front(); q.pop();
int cleft = cur.first.first;
int cright = cur.first.second;
if (cleft > cright) continue; //why would we care
int numtoleft = cur.second.first;
int numtoright = cur.second.second;
if (numtoleft + numtoright == numtot) continue; //why bother
if (cleft == cright) {
pii cur = query(cleft);
if (cur.first + cur.second == 0) return cleft;
continue;
}
bool done = false;
int mid = (cleft + cright)/2;
int omid = mid;
int tookout = 0;
while (mid != cright+1) {
pii cur = query(mid);
if (cur.first + cur.second == numtot) {
q.push(mp(mp(cleft, omid-1),
mp(numtoleft, cur.second + tookout)));
q.push(mp(mp(mid+1, cright),
mp(cur.first, numtoright)));
done = true;
break;
}
else {
tookout++;
if (cur.first + cur.second == 0) return mid;
mid++;
}
}
if (done) continue;
mid = omid-1;
while (mid != cleft-1) {
pii cur = query(mid);
if (cur.first + cur.second == numtot) {
q.push(mp(mp(cleft , mid-1),
mp(numtoleft, cur.second)));
done = true;
break;
}
else {
if (cur.first + cur.second == 0) return mid;
mid--;
}
}
}
return 0;
}
//at most sqrt(n) guys that are not the maximums
//if we query smth not the maximum, we split it in half
//grader can behave adversarily
컴파일 시 표준 에러 (stderr) 메시지
prize.cpp: In function 'int find_best(int)':
prize.cpp:49:6: warning: unused variable 'aft' [-Wunused-variable]
int aft = query(mxind).second;
^~~
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