Submission #783227

#TimeUsernameProblemLanguageResultExecution timeMemory
783227Dan4LifeSightseeing in Kyoto (JOI22_kyoto)C++17
0 / 100
4 ms8276 KiB
#include <bits/stdc++.h> using namespace std; #define pb push_back #define int long long #define all(a) begin(a),end(a) const int mxN = (int)1e3+10; bool vis[mxN]; int n, m, dp[mxN][mxN]; int a[100010], b[100010]; vector<array<int,2>> A, B; int32_t main() { cin >> n >> m; for(int i = 0; i < n; i++) cin >> a[i]; for(int i = 0; i < m; i++) cin >> b[i]; for(int i = n-1; i >= 0; i--) if(n<=1000 or !i or !vis[a[i]]) vis[a[i]]=1, A.pb({a[i],i}); memset(vis,0,sizeof(vis)); for(int i = m-1; i >= 0; i--) if(m<=1000 or !i or !vis[b[i]]) vis[b[i]]=1, B.pb({b[i],i}); reverse(all(A)), reverse(all(B)); n = A.size(), m = B.size(); memset(dp,63,sizeof(dp)); dp[1][1] = 0; for(int i = 1; i <= n; i++){ for(int j = 1; j <= m; j++){ if(i>1) dp[i][j] = min(dp[i][j], dp[i-1][j]+B[j-1][0]*(A[i-1][1]-A[i-2][1])); if(j>1) dp[i][j] = min(dp[i][j], dp[i][j-1]+A[i-1][0]*(B[j-1][1]-B[j-2][1])); } } cout << dp[n][m]; }
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