제출 #779376

#제출 시각아이디문제언어결과실행 시간메모리
779376OrazBGlobal Warming (CEOI18_glo)C++17
28 / 100
2073 ms3412 KiB
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
             tree_order_statistics_node_update>
    ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second

int binary(vector<int> vec, int x){
	int l = 0, r = vec.size()-1, pos = 0;
	while(l <= r){
		int md = (l+r)/2;
		if (vec[md] >= x) r = md - 1;
		else{
			pos = md;
			l = md + 1;
		}
	}
	return pos;
}

int LIS(int n, vector<int> a){
	vector<int> vec(n+1, 1e9+7);
	vec[0] = -1e9;
	int mx = 0;
	for (int i = 1; i <= n; i++){
		int pos = binary(vec, a[i]);
		// if (a[0] == -1) cout << pos << " ";
		vec[pos+1] = min(vec[pos+1], a[i]);
		mx = max(mx, pos+1);
	}
	// if (mx == 6){
	// 	if (a[0] == -1) exit(0);
	// 	for (int i = 1; i <= n; i++){
	// 		cout << a[i] << " ";
	// 	}
	// 	cout << '\n';
	// 	a[0] = -1;
	// 	LIS(n, a);
	// }
	return mx;
}

int main ()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	int n, x;
	cin >> n >> x;
	vector<int> a(n+1);
	for (int i = 1; i <= n; i++) cin >> a[i];
	if (!x) return cout << LIS(n, a), 0;
	int mx = 0;
	for (int i = 1; i <= n; i++){
		a[i] -= x;
		mx = max(mx, LIS(n, a));
	}
	cout << mx;
}	
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