Submission #779373

#TimeUsernameProblemLanguageResultExecution timeMemory
779373OrazBGlobal Warming (CEOI18_glo)C++17
28 / 100
2065 ms5320 KiB
#include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> #include <functional> using namespace __gnu_pbds; using namespace std; typedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set; //Dijkstra->set //set.find_by_order(x) x-position value //set.order_of_key(x) number of strictly less elements don't need *set.?? #define N 100005 #define wr cout << "Continue debugging\n"; #define all(x) (x).begin(), (x).end() #define ll long long int #define pii pair <int, int> #define pb push_back #define ff first #define ss second int binary(vector<int> vec, int x){ int l = 0, r = vec.size()-1, pos = 0; while(l <= r){ int md = (l+r)/2; if (vec[md] >= x) r = md - 1; else{ pos = md; l = md + 1; } } return pos; } int LIS(int n, vector<int> a){ vector<int> vec(n+1, 1e9+7); vec[0] = -1e9; int mx = 0; for (int i = 1; i <= n; i++){ int pos = binary(vec, a[i]); // if (a[0] == -1) cout << pos << " "; vec[pos+1] = min(vec[pos+1], a[i]); mx = max(mx, pos+1); } // if (mx == 6){ // if (a[0] == -1) exit(0); // for (int i = 1; i <= n; i++){ // cout << a[i] << " "; // } // cout << '\n'; // a[0] = -1; // LIS(n, a); // } return mx; } int main () { ios::sync_with_stdio(false); cin.tie(0); int n, x; cin >> n >> x; vector<int> a(n+1); for (int i = 1; i <= n; i++) cin >> a[i]; int mx = 0; for (int i = 1; i <= n; i++){ a[i] -= x; mx = max(mx, LIS(n, a)); } cout << mx; }
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