Submission #777681

#TimeUsernameProblemLanguageResultExecution timeMemory
777681epicci23Bigger segments (IZhO19_segments)C++17
13 / 100
1 ms340 KiB
#include "bits/stdc++.h" #pragma optimize ("Bismillahirrahmanirrahim") using namespace std; #define pb push_back #define ff first #define ss second #define endl "\n" #define int long long #define double long double #define sz(x) ((int)(x).size()) #define all(x) (x).begin(), (x).end() #define rall(x) (x).rbegin(), (x).rend() #define what_is(x) cerr << #x << " is " << x << endl; //#define m (l+r)/2 constexpr int N=200005; constexpr int MOD=1000000007; constexpr int INF2 = LLONG_MAX; constexpr int INF=(int)1e18; constexpr int LOG=30; typedef pair<int,int> pii; typedef tuple<int,int,int> tp; typedef priority_queue<pii,vector<pii>,greater<pii>> min_pq; typedef priority_queue<pii> max_pq; typedef long long ll; //to think// /* * graph approach * dp * dividing the problem to smaller statements * finding the real constraint * sqrt decomposition * greedy approach * pigeonhole principle * rewriting the problem/equality * bitwise approaches * binary search if monotonic * divide and conquer * combinatorics * inclusion - exclusion * think like bfs */ inline int in() { int x;cin >> x; return x; } inline string in2() { string x;cin >> x; return x; } void solve() { int n=in(); int ar[n+1]; for(int i=1;i<=n;i++) ar[i]=in(); int pre[n+1]; pre[0]=0; for(int i=1;i<=n;i++) pre[i]=ar[i]+pre[i-1]; pii dp[n+1]; dp[0]={0,0}; auto get=[&](int l,int r) { return pre[r]-pre[l-1]; }; for(int i=1;i<=n;i++) { int l=1,r=i; while(l<r) { int mid=(l+r+1)/2; if(get(mid,i)>=dp[mid-1].ss) l=mid; else r=mid-1; } dp[i]={dp[l-1].ff+1,get(l,i)}; } cout << dp[n].ff << endl; } int32_t main(){ cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(15); int t=1;//cin>> t; for(int i=1;i<=t;i++) { // cout << "Case #" << i << ": "; solve(); } return 0; }

Compilation message (stderr)

segments.cpp:2: warning: ignoring '#pragma optimize ' [-Wunknown-pragmas]
    2 | #pragma optimize ("Bismillahirrahmanirrahim")
      |
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