제출 #777332

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
777332		vjudge1	Sajam (COCI18_sajam)	C++17	45 / 90	53 ms	5196 KiB

sajam

#include <bits/stdc++.h>
using namespace std;
#define int long long
#define OYY 1000000000005
#define faster ios_base::sync_with_stdio(false); cin.tie(NULL);
#define mid (start+end)/2
#define mod 1000000007

int32_t main(){
    faster
    int n,k;
    cin>>n>>k;
    string s[n],ger[n],sor1[n];
    int cev=0,xi=0,oi=0,cev1=0,cev2=0,cev3=0,oim=0,xim=0,gec2=OYY,tr=0;
    for(int i=0;i<n;i++){
        cin>>s[i];
        string f="";
        for(int j=0;j<n;j++){
            if(s[i][j]=='x'){
                f+='o';
                tr++;
            }
            else f+='x';
        }
        ger[i]=f;
    }
    int gec=n*n;
    if(gec%2!=0)gec++;
    gec/=2;
    //cout<<gec<<endl;
    if(tr==n*n/2 && n%2==0){
        cout<<"DA"<<'\n';;
    }
    else if(k>=gec){
       cout<<"DA"<<'\n';
    }
    else{
        for(int i=0;i<n;i++){
            if(ger[i][0]=='o'){
                sor1[i]=ger[i];
            }
            else{
                sor1[i]=s[i];
            }
        }
        int gec=OYY;
        for(int i=0;i<n;i++){
            gec=OYY;
            gec2=OYY;
            xi=0,oi=0;
            oim=0,xim=0;
            for(int j=0;j<n;j++){
                if(sor1[j][i]=='x')xi++;
                else oi++;
            }
            for(int j=0;j<n;j++){
                if(sor1[i][j]=='x')xim++;
                else oim++;
            }
            gec=min(oi,xi);
            gec2=min(oim,xim);
            cev+=gec;
            cev1+=gec2;
            //cout<<cev<<" "<<cev1<<endl;
        }
        for(int i=0;i<n;i++){
            if(ger[0][i]=='o'){
                for(int j=0;j<n;j++){
                    sor1[j][i]=ger[j][i];
                }
            }
            else{
                for(int j=0;j<n;j++){
                    sor1[j][i]=s[j][i];
                }
            }
        }
        gec=OYY;
        for(int i=0;i<n;i++){
            gec=OYY;
            gec2=OYY;
            xi=0,oi=0;
            for(int j=0;j<n;j++){
                if(sor1[i][j]=='x')xi++;
                else oi++;
            }
            for(int j=0;j<n;j++){
                if(sor1[j][i]=='x')xim++;
                else oim++;
            }
            gec=min(xi,oi);
            gec2=min(xim,oim);
            cev2+=gec;
            cev3+=gec2;
            //cout<<cev2<<" "<<cev3<<endl;
        }
        int sonuc=min(cev,min(cev1,min(cev2,cev3)));

    //}
    //////////////////////////////
    for(int i=0;i<n;i++){
            if(ger[i][1]=='o'){
                sor1[i]=ger[i];
            }
            else{
                sor1[i]=s[i];
            }
        }
        gec=OYY;
        for(int i=0;i<n;i++){
            gec=OYY;
            gec2=OYY;
            xi=0,oi=0;
            oim=0,xim=0;
            for(int j=0;j<n;j++){
                if(sor1[j][i]=='x')xi++;
                else oi++;
            }
            for(int j=0;j<n;j++){
                if(sor1[i][j]=='x')xim++;
                else oim++;
            }
            gec=min(oi,xi);
            gec2=min(oim,xim);
            cev+=gec;
            cev1+=gec2;
        }
        for(int i=0;i<n;i++){
            if(ger[1][i]=='o'){
                for(int j=0;j<n;j++){
                    sor1[j][i]=ger[j][i];
                }
            }
            else{
                for(int j=0;j<n;j++){
                    sor1[j][i]=s[j][i];
                }
            }
        }
        gec=OYY;
        for(int i=0;i<n;i++){
            gec=OYY;
            gec2=OYY;
            xi=0,oi=0;
            for(int j=0;j<n;j++){
                if(sor1[i][j]=='x')xi++;
                else oi++;
            }
            for(int j=0;j<n;j++){
                if(sor1[j][i]=='x')xim++;
                else oim++;
            }
            gec=min(xi,oi);
            gec2=min(xim,oim);
            cev2+=gec;
            cev3+=gec2;
            //cout<<cev2<<" "<<cev3<<endl;
        }
        int son2=min(cev,min(cev1,min(cev2,cev3)));
        if(min(sonuc,son2)<=k)cout<<"DA"<<'\n';
        else cout<<"NE"<<'\n';
}
    return 0;
}

• Subtask 1: 15 / 15
• Subtask 2: 0 / 15
• Subtask 3: 15 / 15
• Subtask 4: 15 / 15
• Subtask 5: 0 / 15
• Subtask 6: 0 / 15