이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second
#define pv pair<pii,vector<bool>>
int n;
vector<int> E[N];
pv F(int i, vector<bool> vis){
int cnt = 0;
vector<bool> nw(n+1, 0);
queue<pii> q; q.push({i, 1});
int sum = 0;
while(!q.empty()){
int x = q.front().ff, c = q.front().ss;
q.pop();
if (nw[x]) continue;
nw[x] = 1;
cnt++;
for (auto j : E[x]) if (!nw[j] and !vis[j]) q.push({j, c+1});
sum += c;
}
return {{cnt, -sum}, nw};
}
int main ()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n;
for (int i = 1; i <= n; i++){
int k;
cin >> k;
while(k--){
int x;
cin >> x;
E[x].pb(i);
}
}
int sum = 0;
vector<bool> vis(n+1, 0);
while(1){
pv mx;
for (int i = 1; i <= n; i++){
if (!vis[i]){
pv X = F(i, vis);
mx = max(mx, X);
}
}
if (!mx.ff.ff) break;
sum += -mx.ff.ss;
vector<bool> nw = mx.ss;
for (int i = 1; i <= n; i++){
vis[i] = max(vis[i], nw[i]);
}
}
cout << sum << '\n';
}
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