이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define endl '\n'
int pt = 0;
pair<ll,ll> tree[3*6000000];
int lft[3*6000000];
int rt[3*6000000];
int P[100005][30];
int root[100005];
vector<int> dep(100005);
vector<ll> w[100005];
vector<pair<int,int>> adj[100005];
int P2[100005][30];
void update(int node,int prv,int l,int r,ll idx,ll val){
if(l == r) return tree[node] = make_pair(tree[prv].first+l*val,tree[prv].second+val),void();
int md = l + r >> 1;
if(idx<=md){
int tmp = lft[prv];
lft[node] = ++pt;
rt[node] = rt[prv];
update(lft[node],tmp,l,md,idx,val);
}
else {
int tmp = rt[prv];
rt[node] = ++pt;
lft[node] = lft[prv];
update(rt[node],tmp,md+1,r,idx,val);
}
tree[node] = make_pair(tree[lft[node]].first+tree[rt[node]].first,tree[lft[node]].second+tree[rt[node]].second);
}
void update(int a,int b,ll val,ll frq){
if(!root[a]) root[a] = ++pt;
update(root[a],root[b],1,1e9,val,frq);
}
void dfs(int node,int par,int id){
P[node][0] = par;
P2[node][0] = w[id].size();
for(int k=1;k<30;k++) P[node][k] = P[P[node][k-1]][k-1],P2[node][k] = P2[node][k-1] + P2[P[node][k-1]][k-1];
for(auto e : adj[node]){
int ch = e.first;
if(ch == par) continue;
dep[ch] = dep[node] + 1;
update(ch,node,1,0);
for(auto ww : w[e.second]){
update(ch,ch,ww,1);
}
dfs(ch,node,e.second);
}
}
int lca(int a,int b){
if(dep[a]<dep[b]) swap(a,b);
if(a == b) return a;
for(int k=29;k>=0;k--){
if(dep[a]-(1<<k)>=dep[b]){
a = P[a][k];
}
}
if(a == b){
return a;
}
for(int i=29;i>=0;i--){
if(P[a][i]!=P[b][i]){
a = P[a][i];
b = P[b][i];
}
}
return P[a][0];
}
int calc(int a,int b){
if(dep[a]<dep[b]) swap(a,b);
if(a == b) return a;
int ret = 0;
for(int k=29;k>=0;k--){
if(dep[a]-(1<<k)>=dep[b]){
ret += P2[a][k];
a = P[a][k];
}
}
if(a == b){
return ret;
}
for(int i=29;i>=0;i--){
if(P[a][i]!=P[b][i]){
ret += P2[a][i];
ret += P2[b][i];
a = P[a][i];
b = P[b][i];
}
}
ret += P2[a][0] + P2[b][0];
return ret;
}
ll query(int a,int b,int c,int l,int r,ll x){
if(l == r){
ll z = tree[a].second+tree[b].second-2*tree[c].second;
return min(x/(ll)l,z);
}
pair<ll,ll> sumOfL = make_pair(tree[lft[a]].first+tree[lft[b]].first-2LL*tree[lft[c]].first,tree[lft[a]].second+tree[lft[b]].second-2LL*tree[lft[c]].second);
pair<ll,ll> sumOfR = make_pair(tree[rt[a]].first+tree[rt[b]].first-2LL*tree[rt[c]].first,tree[rt[a]].second+tree[rt[b]].second-2LL*tree[rt[c]].second);
int md = l + r >> 1;
if(sumOfL.first>x) return query(lft[a],lft[b],lft[c],l,md,x);
return sumOfL.second + query(rt[a],rt[b],rt[c],md+1,r,x-sumOfL.first);
}
void solve(){
int n,m,q;
cin>>n>>m>>q;
for(int i=0;i<n-1;i++){
int a,b;
cin>>a>>b;
adj[a].push_back({b,i+1});
adj[b].push_back({a,i+1});
}
for(int i=0;i<m;i++){
ll a,b;
cin>>a>>b;
w[a].push_back(b);
}
dfs(1,0,0);/*
for(int i=1;i<=n;i++) {
cout<<tree[root[i]].first<<' ';
}
cout<<endl;*/
while(q--){
ll u,v,a,b;
cin>>u>>v>>a>>b;
ll z = query(root[u],root[v],root[lca(u,v)],1,1e9,b);
ll ans = a - (calc(u,v)-z);
cout<<(ans<0?-1:ans)<<endl;
}
}
int main()
{
ios_base::sync_with_stdio(0);
cin.tie(0); cout.tie(0);
int t=1;
// cin>>t;
while(t--){
solve();
}
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
currencies.cpp: In function 'void update(int, int, int, int, ll, ll)':
currencies.cpp:18:16: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
18 | int md = l + r >> 1;
| ~~^~~
currencies.cpp: In function 'll query(int, int, int, int, int, ll)':
currencies.cpp:102:16: warning: suggest parentheses around '+' inside '>>' [-Wparentheses]
102 | int md = l + r >> 1;
| ~~^~~
currencies.cpp:101:17: warning: variable 'sumOfR' set but not used [-Wunused-but-set-variable]
101 | pair<ll,ll> sumOfR = make_pair(tree[rt[a]].first+tree[rt[b]].first-2LL*tree[rt[c]].first,tree[rt[a]].second+tree[rt[b]].second-2LL*tree[rt[c]].second);
| ^~~~~~
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