이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "cave.h"
#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define pb push_back
#define F first
#define S second
#define enter cout<<'\n';
#define INF 99999999999999999
#define MOD 1000000007
#define all(x) x.begin(),x.end()
/*
#include <stdio.h>
#include <stdlib.h>
#include "cave.h"
#define MAX_N 5000
#define MAX_CALLS 70000
#define fail(s, x...) do { \
fprintf(stderr, s "\n", ## x); \
exit(1); \
} while(0)
#define N koala
#define realS kangaroo
#define realD possum
#define inv platypus
#define num_calls echidna
int N;
int realS[MAX_N];
int realD[MAX_N];
int inv[MAX_N];
int num_calls;
void answer(int S[], int D[]) {
int i;
int correct = 1;
for (i = 0; i < N; ++i)
if (S[i] != realS[i] || D[i] != realD[i]) {
correct = 0;
break;
}
if (correct)
printf("CORRECT\n");
else
printf("INCORRECT\n");
for (i = 0; i < N; ++i) {
if (i > 0)
printf(" ");
printf("%d", S[i]);
}
printf("\n");
for (i = 0; i < N; ++i) {
if (i > 0)
printf(" ");
printf("%d", D[i]);
}
printf("\n");
exit(0);
}
int tryCombination(int S[]) {
int i;
if (num_calls >= MAX_CALLS) {
printf("INCORRECT\nToo many calls to tryCombination().\n");
exit(0);
}
++num_calls;
for (i = 0; i < N; ++i)
if (S[inv[i]] != realS[inv[i]])
return i;
return -1;
}
int init() {
int i, res;
FILE *f = fopen("cave.in", "r");
if (!f)
fail("Failed to open input file.");
res = fscanf(f, "%d", &N);
for (i = 0; i < N; ++i) {
res = fscanf(f, "%d", &realS[i]);
}
for (i = 0; i < N; ++i) {
res = fscanf(f, "%d", &realD[i]);
inv[realD[i]] = i;
}
num_calls = 0;
return N;
}
*/
///********************************************************************************************************
//tryCombination
void exploreCave(int n)
{
int s[n]={ },d[n];
bool no[n]={ };
for(int i=0;i<n;i++)
{
ll ans1=tryCombination(s),ans;
if(ans1==-1)
ans1=INF;
ll pos=0;
for(int j=0;(1<<j)<n;j++)
{
for(int c=0;c<n;c++)
if(!no[c] && (c&(1<<j)))
s[c]=1;
ans=tryCombination(s);
if(ans==-1)
ans=INF;
if(ans1>i && ans==i)
pos+=(1<<j);
if(ans1==i && ans>i)
pos+=(1<<j);
for(int c=0;c<n;c++)
if(!no[c] && (c&(1<<j)))
s[c]=0;
}
d[pos]=i;
s[pos]=((ans1>i)?0:1);
no[pos]=1;
}
answer(s,d);
}
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