This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
// Om Namah Shivaya
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
template<typename T> using Tree = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
typedef long long int ll;
typedef long double ld;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL)
#define pb push_back
#define endl '\n'
#define sz(a) a.size()
#define setbits(x) __builtin_popcountll(x)
#define ff first
#define ss second
#define conts continue
#define ceil2(x, y) ((x + y - 1) / (y))
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
#define yes cout << "Yes" << endl
#define no cout << "No" << endl
#define rep(i, n) for(int i = 0; i < n; ++i)
#define rep1(i, n) for(int i = 1; i <= n; ++i)
#define rev(i, s, e) for(int i = s; i >= e; --i)
#define trav(i, a) for(auto &i : a)
template<typename T>
void amin(T &a, T b) {
a = min(a, b);
}
template<typename T>
void amax(T &a, T b) {
a = max(a, b);
}
#ifdef LOCAL
#include "debug.h"
#else
#define debug(x) 42
#endif
/*
refs:
edi of apio 2007 backup
*/
const int MOD = 1e9 + 7;
const int N = 1e5 + 5;
const int inf1 = int(1e9) + 5;
const ll inf2 = ll(1e18) + 5;
void solve(int test_case)
{
ll n; cin >> n;
vector<ll> a(n+5);
rep1(i,n) cin >> a[i];
set<array<ll,3>> segs;
set<array<ll,3>> costs;
rep1(i,n){
segs.insert({i,i+1,a[i]});
costs.insert({a[i],i,i+1});
}
ll ans = 0;
rep1(iter,ceil2(n,2)){
auto [mx,l,r] = *costs.rbegin();
ans += mx;
cout << ans << endl;
auto it = segs.lower_bound({l,r,mx});
array<ll,3> ar1, ar2;
ar1.fill(-1);
ar2.fill(-1);
if(it != segs.begin()){
ar1 = *prev(it);
}
if(next(it) != segs.end()){
ar2 = *next(it);
}
if(ar1[0] != -1){
segs.erase(ar1);
costs.erase({ar1[2], ar1[0], ar1[1]});
}
if(ar2[0] != -1){
segs.erase(ar2);
costs.erase({ar2[2], ar2[0], ar2[1]});
}
if(ar1[0] != -1 and ar2[0] != -1){
ll l = ar1[0], r = ar2[1], cost = ar1[2]+ar2[2]-mx;
segs.insert({l,r,cost});
costs.insert({cost,l,r});
}
segs.erase({l,r,mx});
costs.erase({mx,l,r});
}
}
int main()
{
fastio;
int t = 1;
// cin >> t;
rep1(i, t) {
solve(i);
}
return 0;
}
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