이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <int, int>
#define pb push_back
#define ff first
#define ss second
const ll INF = 1e18;
int n, k;
int main ()
{
ios::sync_with_stdio(false);
cin.tie(0);
cin >> n >> k;
vector<ll>a(n+1), pref(n+1, 0);
for (int i = 1; i <= n; i++){
cin >> a[i];
pref[i] = pref[i-1]+a[i];
}
vector<int> vec;
ll sum = 0;
set<pii> s = {{1, n}};
while(k--){
ll mx = 0, l2 = 0, r2 = 0, idx = 0;
for (auto z : s){
ll x = 0, y = 0, mn = INF;
int l = z.ff, r = z.ss, pos = 0;
while(l <= r){
int md = (l+r)/2;
ll A = pref[md]-pref[z.ff-1], B = pref[z.ss]-pref[md];
if (mn > abs(A-B)){
mn = abs(A-B);
x = A; y = B;
pos = md;
}
(A>B ? r=md-1 : l=md+1);
}
if (mx < x*y){
mx = x*y;
l2 = z.ff;
r2 = z.ss;
idx = pos;
}
}
sum += mx;
s.erase({l2, r2});
if (l2 != idx) s.insert({l2, idx});
if (r2 != idx) s.insert({idx+1, r2});
vec.pb(idx);
}
cout << sum << '\n';
for (auto i : vec) cout << i << " ";
}
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