제출 #76773

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
76773		born2rule	Palembang Bridges (APIO15_bridge)	C++14	0 / 100	2 ms	944 KiB

bridge

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

#define ll long long
#define db long double
#define ii pair<int,int>
#define vi vector<int>
#define fi first
#define se second
#define sz(a) (int)(a).size()
#define all(a) (a).begin(),(a).end()
#define pb push_back
#define mp make_pair
#define FN(i, n) for (int i = 0; i < (int)(n); ++i)
#define FEN(i,n) for (int i = 1;i <= (int)(n); ++i)
#define rep(i,a,b) for(int i=a;i<b;i++)
#define repv(i,a,b) for(int i=b-1;i>=a;i--)
#define SET(A, val) memset(A, val, sizeof(A))
typedef tree<int ,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set ;
// order_of_key (val): returns the no. of values less than val
// find_by_order (k): returns the kth largest element.(0-based)
#define TRACE
#ifdef TRACE
#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)
template <typename Arg1>
void __f(const char* name, Arg1&& arg1){
  cerr << name << " : " << arg1 << std::endl;
}
template <typename Arg1, typename... Args>
void __f(const char* names, Arg1&& arg1, Args&&... args){
  const char* comma = strchr(names + 1, ','); cerr.write(names, comma - names) << " : " << arg1<<" | ";__f(comma+1, args...);
}
#else
#define trace(...)
#endif
const int N=100005;
map<int,vi> m1,m2;
vi v;
int st[N],en[N],cnt;
ordered_set s;
int main()
{
  std::ios::sync_with_stdio(false);
  cin.tie(NULL) ; cout.tie(NULL) ;
  int k,n;
  cin>>k>>n;
  ll sum=0;
  ll tmppost=0,tmppre=0,distpost=0,distpre=0,cntpost=0,cntpre=0;
  ll totsum=0;
  rep(i,1,n+1)
    {
      char x,y;
      int st,en;
      cin>>x>>st>>y>>en;
      if(st>en) swap(st,en);
      if(x==y) sum+=en-st;
      else
	{
	  v.pb(st); v.pb(en); cnt++;
	  m1[st].pb(cnt); m2[en].pb(cnt);
	  ::st[cnt]=st; ::en[cnt]=en;
	  tmppost+=en-st; cntpost++;
	  distpost+=st;
	  totsum+=en-st;
	}
    }
  sort(all(v));
  v.erase(unique(all(v)),v.end());
  ll ans=LLONG_MAX;
  for(int x:v)
    {
      ll curr=0;
      //add which have st and en after this
      curr+=tmppost+(ll)2*(distpost-(ll)cntpost*x);
      //add which have st and en before this
      curr+=tmppre+(ll)2*((ll)cntpre*x-distpre);
      //add which have st before and en after
      curr+=totsum-tmppost-tmppre;
      for(int ind:m1[x])//these elements are starting here
	{
	  tmppost-=en[ind]-st[ind];
	  distpost-=st[ind];
	  cntpost--;
	}
      for(int ind:m2[x])//these elements are ending here
	{
	  tmppre+=en[ind]-st[ind];
	  distpre+=en[ind];
	  cntpre++;
	}
      ans=min(ans,curr+cnt);
    }
  ans+=sum;
  cout<<ans<<endl;
  return 0 ;
}

• Subtask 1: 0 / 8
• Subtask 2: 0 / 14
• Subtask 3: 0 / 9
• Subtask 4: 0 / 32
• Subtask 5: 0 / 37