#include<bits/stdc++.h>
#include "secret.h"
typedef long long ll;
typedef unsigned long long ull;
typedef long double ld;
typedef double db;
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#define pbds tree<pair<int, int>, null_type, less<pair<int, int>>,rb_tree_tag, tree_order_statistics_node_update>
using namespace __gnu_pbds;
ll gcd(ll a , ll b) {return b ? gcd(b , a % b) : a ;} // greatest common divisor (PGCD)
ll lcm(ll a , ll b) {return (a * b) / gcd(a , b);} // least common multiple (PPCM)
int dx[8] = {1, 0, 0, -1, 1, 1, -1, -1};
int dy[8] = {0, 1, -1, 0, 1, -1, -1, 1};
#define endl "\n"
#define ss second
#define ff first
#define all(x) (x).begin() , (x).end()
#define pb push_back
#define vi vector<int>
#define vii vector<pair<int,int>>
#define vl vector<ll>
#define vll vector<pair<ll,ll>>
#define pii pair<int,int>
#define pll pair<ll,ll>
#define pdd pair<double,double>
#define vdd vector<pdd>
#define speed ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
using namespace std;
////////////////////Only Clear Code//////////////////////////
const int mx = 1005;
const int LOG = 25;
const int inf = 1e9+5;
const ll mod = 1e9+7;
int range[mx][mx];
void Solve(int l, int r) {
if (r - l <= 1) {
return;
}
int md = (l + r) / 2;
for (int i = md - 1; i >= l; --i) {
if (range[i][md] == -1) {
range[i][md] = Secret(range[i][i + 1], range[i + 1][md]);
}
}
for (int i = md + 1; i <= r; ++i) {
if (range[md][i] == -1) {
range[md][i] = Secret(range[md][i - 1], range[i - 1][i]);
}
}
Solve(l, md);
Solve(md, r);
}
void Init(int N, int A[]){
for(int i = 0; i <= N;i++){
for(int j = 0; j <= N;j++){
range[i][j] = -1;
}
}
for(int i = 0; i < N;i++){
range[i][i+1] = A[i];
}
Solve(0, N);
}
int Query(int L, int R){
for(int i = L+1;i <= R;i++){
if(range[L][i] != -1 && range[i][R+1] != -1){
return Secret(range[L][i], range[i][R+1]);
}
}
return range[L][R+1];
}
/*
NEVER GIVE UP!
DOING SMTHNG IS BETTER THAN DOING NTHNG!!!
Your Guide when stuck:
- Continue keyword only after reading the whole input
- Don't use memset with testcases
- Check for corner cases(n=1, n=0)
- Check where you declare n(Be careful of declaring it globally and in main)
*/
# |
결과 |
실행 시간 |
메모리 |
Grader output |
1 |
Correct |
121 ms |
4372 KB |
Output is correct - number of calls to Secret by Init = 3084, maximum number of calls to Secret by Query = 1 |
2 |
Correct |
115 ms |
4376 KB |
Output is correct - number of calls to Secret by Init = 3092, maximum number of calls to Secret by Query = 1 |
3 |
Correct |
112 ms |
4408 KB |
Output is correct - number of calls to Secret by Init = 3101, maximum number of calls to Secret by Query = 1 |
4 |
Correct |
411 ms |
8200 KB |
Output is correct - number of calls to Secret by Init = 6989, maximum number of calls to Secret by Query = 1 |
5 |
Correct |
400 ms |
8172 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |
6 |
Correct |
388 ms |
8216 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |
7 |
Correct |
393 ms |
8216 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |
8 |
Correct |
419 ms |
8212 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |
9 |
Correct |
402 ms |
8128 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |
10 |
Correct |
394 ms |
8264 KB |
Output is correct - number of calls to Secret by Init = 6997, maximum number of calls to Secret by Query = 1 |