제출 #766706

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
766706		khshg	Arranging Shoes (IOI19_shoes)	C++14	30 / 100	1082 ms	13208 KiB

shoes

#include<bits/stdc++.h>
using namespace std;
 
using ll = long long;
using ld = long double;
using str = string;
 
using pi = pair<int, int>;
using pl = pair<ll, ll>;
using pd = pair<ld, ld>;
#define mp make_pair
#define ff first
#define ss second
 
#define ar array
template<class T> using V = vector<T>;
using vi = V<int>;
using vb = V<bool>;
using vl = V<ll>;
using vd = V<ld>;
using vs = V<str>;
using vpi = V<pi>;
using vpl = V<pl>;
using vpd = V<pd>;
 
#define sz(x) (int)((x).size())
#define bg(x) begin(x)
#define all(x) bg(x), end(x)
#define rall(x) (x).rbegin(), (x).rend()
#define sor(x) sort(all(x))
#define rsz resize
#define ins insert
#define pb push_back
#define eb emplace_back
#define ft front()
#define bk back()
#define lb lower_bound
#define ub upper_bound
 
#define FOR(i, a, b) for(int i = (a); i < (b); ++i)
#define F0R(i, a) FOR(i, 0, a)
#define ROF(i, a, b) for(int i = (b) - 1; i >= (a); --i)
#define R0F(i, a) ROF(i, 0, a)
#define rep(a) F0R(_, a)
#define trav(a, x) for(auto& a : x)
 
template<class T> bool ckmin(T& a, const T& b) { return (b < a ? a = b, 1 : 0); }
template<class T> bool ckmax(T& a, const T& b) { return (b > a ? a = b, 1 : 0); }

ll count_swaps(vi S) {
	int N = sz(S) >> 1;
	{
		map<int, int> c;
		trav(u, S) c[abs(u)];
		int tim3 = 1; trav(u, c) u.ss = tim3++;
		trav(u, S) u = c[abs(u)] * (u < 0 ? -1 : 1);
	}
	vi A; trav(u, S) if(u > 0) A.eb(u);
	sor(A);
	ll ans = 0x3f3f3f3f;
	do {
		V<vi> l(N + 1), r(N + 1);
		F0R(i, 2 * N) {
			if(S[i] < 0) l[-S[i]].eb(i);
			else r[S[i]].eb(i);
		}
		ll cur = 0;
		F0R(i, N) {
			int lsh = 2 * i;
			int dis = 0x3f3f3f3f, ind = -1;
			F0R(j, sz(l[A[i]])) {
				if(ckmin(dis, abs(lsh - l[A[i]][j]))) ind = j;
			}
			if(ind == -1) {
				cout << "wtf\n";
				exit(1);
			}
			cur += dis;
			FOR(j, 1, N + 1) {
				trav(u, l[j]) if(u < l[A[i]][ind]) ++u;
				trav(u, r[j]) if(u < l[A[i]][ind]) ++u;
			}
			l[A[i]].erase(bg(l[A[i]]) + ind);
			lsh = 2 * i + 1;
			dis = 0x3f3f3f3f, ind = -1;
			F0R(j, sz(r[A[i]])) {
				if(ckmin(dis, abs(lsh - r[A[i]][j]))) ind = j;
			}
			if(ind == -1) {
				cout << "wtf\n";
				exit(1);
			}
			cur += dis;
			FOR(j, 1, N + 1) {
				trav(u, l[j]) if(u < r[A[i]][ind]) ++u;
				trav(u, r[j]) if(u < r[A[i]][ind]) ++u;
			}
			r[A[i]].erase(bg(r[A[i]]) + ind);
		}
		ckmin(ans, cur);
	} while(next_permutation(all(A)));
	return ans;
}

• Subtask 1: 10 / 10
• Subtask 2: 20 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 15
• Subtask 5: 0 / 20
• Subtask 6: 0 / 15