제출 #765840

#제출 시각아이디문제언어결과실행 시간메모리
765840ono_de206Meetings (IOI18_meetings)C++14
19 / 100
5529 ms40264 KiB
#include "meetings.h" #include<bits/stdc++.h> using namespace std; #define in insert #define all(x) x.begin(),x.end() #define pb push_back #define eb emplace_back #define ff first #define ss second // #define int long long typedef long long ll; typedef vector<int> vi; typedef set<int> si; typedef multiset<int> msi; typedef pair<int, int> pii; typedef vector<pii> vpii; const int mxn = 8e5 + 10; const long long inf = 1e18; int h[mxn], LOG[mxn]; long long dp1[mxn], dp2[mxn]; pair<int, int> sp1[mxn][22], sp2[mxn][22]; vector<long long> minimum_costs(vector<int> H, vector<int> L, vector<int> R) { int Q = L.size(), n = H.size(); vector<long long> ret(Q); for(int i = 1; i <= n; i++) { h[i] = H[i - 1]; sp1[i][0] = {h[i], i}; sp2[i][0] = {h[i], -i}; } for(int i = 1; i <= 20; i++) { for(int j = 1; j + (1 << i) - 1 <= n; j++) { sp1[j][i] = max(sp1[j][i - 1], sp1[j + (1 << (i - 1))][i - 1]); sp2[j][i] = max(sp2[j][i - 1], sp2[j + (1 << (i - 1))][i - 1]); } } stack<pair<int, int>> s; for(int i = 1; i <= n; i++) { while(s.size() && s.top().ff <= h[i]) s.pop(); if(s.size() == 0) dp1[i] = i * h[i]; else dp1[i] = dp1[s.top().ss] + 1LL * h[i] * (i - s.top().ss); s.push({h[i], i}); } while(s.size()) s.pop(); for(int i = n; i >= 1; i--) { while(s.size() && s.top().ff <= h[i]) s.pop(); if(s.size() == 0) dp2[i] = (n - i + 1) * h[i]; else dp2[i] = dp2[s.top().ss] + 1LL * h[i] * (s.top().ss - i); s.push({h[i], i}); } for(int i = 2; i <= n; i++) { LOG[i] = LOG[i / 2] + 1; } auto get1 = [&](int l, int r) -> pair<int, int> { int lg = LOG[r - l + 1]; return max(sp1[l][lg], sp1[r - (1 << lg) + 1][lg]); }; auto get2 = [&](int l, int r) -> pair<int, int> { int lg = LOG[r - l + 1]; return max(sp2[l][lg], sp2[r - (1 << lg) + 1][lg]); }; for(int i = 0; i < Q; i++) { int l = L[i] + 1, r = R[i] + 1; ret[i] = inf; for(int j = l; j <= r; j++) { auto mx1 = get1(l, j); auto mx2 = get2(j, r); mx2.ss *= -1; long long tmp = dp1[j] + dp2[j] - dp1[mx1.ss] - dp2[mx2.ss] + 1LL * (mx1.ss - l + 1) * mx1.ff + 1LL * (r - mx2.ss + 1) * mx2.ff - h[j]; ret[i] = min(ret[i], tmp); } } return ret; }
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