제출 #76528

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
76528		Noam527	Pinball (JOI14_pinball)	C++14	0 / 100	2 ms	508 KiB

pinball

#include <bits/stdc++.h>
#define endl '\n'
#define debug cout << "ok" << endl
#define finish(x) return cout << x << endl, 0
typedef long long ll;
typedef long double ldb;
const int md = 1e9 + 7;
const ll hs = 199, inf = 1e18;
const ldb eps = 1e-9, pi = acos(-1);
using namespace std;

struct segtree {
	int n;
	vector<ll> tree;
	segtree() {}
	segtree(int size) {
		n = max(2, size);
		while (n != (n & -n)) n += (n & -n);
		tree.resize(2 * n, inf);
	}
	void fix(int x) {
		tree[x] = min(tree[2 * x + 1], tree[2 * x + 2]);
	}
	void upd(int pos, ll x) {
		pos += n - 1;
		tree[pos] = min(tree[pos], x);
		pos = (pos - 1) / 2;
		while (pos) {
			fix(pos);
			pos = (pos - 1) / 2;
		}
		fix(0);
	}
	ll query(int l, int r) {
		ll rtn = inf;
		for (l += n - 1, r += n - 1; l < r; l = (l - 1) / 2, r = (r - 1) / 2) {
			if (!(l & 1)) rtn = min(rtn, tree[l++]);
			if (r & 1) rtn = min(rtn, tree[r--]);
		}
		if (l == r) rtn = min(rtn, tree[l]);
		return rtn;
	}
	ll operator [](int pos) {
		return tree[pos + n - 1];
	}
};

struct obj {
	ll l, r, p, c;
	obj() {}
	obj(ll lll, ll rr, ll pp, ll cc) {
		l = lll;
		r = rr;
		p = pp;
		c = cc;
	}
};

int n, m;
vector<obj> a;
segtree L, R;

int main() {
	ios::sync_with_stdio(0), cin.tie(0);

	cin >> n >> m;
	a.resize(n);
	map<int, int> comp;
	for (int i = 0, par[4]; i < n; i++) {
		cin >> par[0] >> par[1] >> par[2] >> par[3];
		comp[par[0]] = comp[par[1]] = comp[par[2]] = 0;
		a[i] = obj(par[0], par[1], par[2], par[3]);
	}
	int x = 0;
	for (auto &i : comp) i.second = x++;
	for (auto &i : a) {
		i.l = comp[i.l];
		i.r = comp[i.r];
		i.p = comp[i.p];
	}
	m = comp.size();
	L = R = segtree(m);
	ll ans = inf;
	for (const auto &i : a) {
		ans = min(ans, (i.r == m - 1 ? 0 : R.query(i.l, i.r)) + (i.l == 0 ? 0 : L.query(i.l, i.r)) + i.c);
		if (i.r == m - 1)
			R.upd(i.p, i.c);
		else
			R.upd(i.p, i.c + R.query(i.l, i.r));
		if (i.l == 0)
			L.upd(i.p, i.c);
		else
			L.upd(i.p, i.c + L.query(i.l, i.r));
	}
	if (ans > (ll)n * 1e9) finish(-1);
	finish(ans);
}

• Subtask 1: 0 / 11
• Subtask 2: 0 / 18
• Subtask 3: 0 / 22
• Subtask 4: 0 / 49