제출 #763898

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
763898		gg123_pe	서열 (APIO23_sequence)	C++17	40 / 100	285 ms	12416 KiB

sequence

#include "sequence.h"
#include <bits/stdc++.h> 
using namespace std;

#define f(i,a,b) for(int i = a; i < b; i++)
#define fa(i,a,b) for(int i = a; i >= b; i--)

const int N = 5e5 + 5; 

int n; 
int bit[N], c[N]; 

void upd(int x, int val){
    for(; x < N; x = (x|(x+1))) bit[x] += val; 
}
int sum(int x){
    int res = 0;
    for(; x >= 0; x = (x&(x+1)) - 1) res += bit[x];  
    return res; 
}
int get(int x){
    int l = 1, r = n; 
    while(l < r){
        int m = (l+r)>>1; 
        if(sum(m) >= x) r = m; 
        else l = m+1; 
    }
    return c[l]; 
}
int subtask_2(vector <int> A){
    int ans = 1; 
    f(i,0,n){
        c[A[i]]++; 
        upd(A[i], 1); 

        f(j,i,n){
            int l = j - i + 1; 
            if(l&1){
                ans = max(ans, get((l+1)/2)); 
            }
            else{
                ans = max(ans, get(l/2)); 
                ans = max(ans, get(l/2 + 1)); 
            }
            if(j+1 < n) {
                c[A[j+1]]++; 
                upd(A[j+1], 1); 
            }
        }
        f(j,i,n){
            c[A[j]]--; 
            upd(A[j], -1); 
        }
    }
    return ans;
}
int id(int pos){
    if(pos == 0) return 0; 
    if(c[1] >= pos) return 1; 
    if(c[1] + c[2] >= pos) return 2; 
    return 3; 
}

int res(vector <int> v){
    vector <int> aux, mini; 
    int len = v.size(), ans = 1; 
    f(i,0,len) {
        aux.push_back(v[i] - 2*i); 
        mini.push_back(v[i] - 2*i); 
    }
    fa(i,len-2,0) mini[i] = min(mini[i+1], mini[i]); 

    f(i,0,len-1){
        int ult = aux[i] + 1; // <= ult
        if(mini[i+1] > ult) continue; 
        int l = i+1, r = len-1; 
        while(l < r){
            int m = (l+r+1)>>1; 
            if(mini[m] > ult) r = m-1;  
            else l = m; 
        }
        ans = max(ans, l-i+1); 
    }
    return ans; 
}
int subtask_4(vector <int> A){
    for(int x: A) c[x]++; 
    int p1 = 0, p2 = 0; 
    if(n&1) p1 = (n+1)/2; 
    else p1 = n/2, p2 = p1 + 1; 

    if(id(p1) == 1 or id(p1) == 3) return c[id(p1)]; 
    if(id(p2) == 1 or id(p2) == 3) return c[id(p2)]; 
    if(c[2] > c[1] and c[2] > c[3]) return c[2]; 

    int ans = c[2];
    vector <int> P1, P3; 
    f(i,0,n){
        if(A[i] == 1) P1.push_back(i); 
        if(A[i] == 3) P3.push_back(i); 
    }
    ans = max(ans, res(P1)); 
    ans = max(ans, res(P3)); 
    return ans; 
}
int sequence(int Ni, vector<int> A) {
    n = Ni; 

    if(n <= 2000) return subtask_2(A); 
    
    int maxi = 0; 
    for(int x: A) maxi = max(maxi, x); 

    if(maxi <= 3) return subtask_4(A); 
    return 0; 
}

• Subtask 1: 11 / 11
• Subtask 2: 17 / 17
• Subtask 3: 0 / 7
• Subtask 4: 12 / 12
• Subtask 5: 0 / 13
• Subtask 6: 0 / 22
• Subtask 7: 0 / 18