이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//Dijkstra->set
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <ll, int>
#define pb push_back
#define ff first
#define ss second
ll max_weights(int n, int m, vector<int> x, vector<int> y, vector<int> w){
int nn = *max_element(all(y));
vector<vector<ll>> a(n+1, vector<ll> (nn+1, 0));
bool sub1 = 0, sub2 = 0;
ll sum = 0;
for (int i = 0; i < m; i++){
a[x[i]+1][y[i]+1] = w[i];
if (x[i]%2) sub1 = 1;
if (x[i] > 1) sub2 = 1;
sum += w[i];
}
if (!sub1) return sum;
for (int i = 1; i <= n; i++){
for (int j = 1; j <= nn; j++){
a[i][j] += a[i][j-1];
}
}
if (!sub2) return max(a[1][nn], a[2][nn]);
vector<vector<vector<ll>>> dp(n+1, vector<vector<ll>>(nn+1, vector<ll>(nn+1, 0)));
for (int j = 0; j <= nn; j++){
for (int k = 0; k <= nn; k++){
if (k <= j) dp[2][j][k] = a[1][j]-a[1][k];
else dp[2][j][k] = a[2][k]-a[2][j];
}
}
ll ans = 0;
for (int i = 3; i <= n; i++){
for (int j = 0; j <= nn; j++){
for (int k = 0; k <= nn; k++){
if (k <= j){
for (int z = 0; z <= nn; z++){
ll x = max(0ll, a[i-1][j]-a[i-1][max(z,k)]);
dp[i][j][k] = max(dp[i][j][k], x+dp[i-1][k][z]);
}
}else{
ll mx = 0;
for (int z = 0; z <= nn; z++) mx = max(mx, dp[i-1][k][z]);
dp[i][j][k] = max(dp[i][j][k], mx+a[i][k]-a[i][j]);
}
if (i == n) ans = max(ans, dp[i][j][k]);
}
}
}
return ans;
}
// int main ()
// {
// int n, m;
// cin >> n >> m;
// vector<int> x(m), y(m), w(m);
// for (int i = 0; i < m; i++) cin >> x[i] >> y[i] >> w[i];
// cout << max_weights(n,m,x,y,w);
// }
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