제출 #762414

#제출 시각아이디문제언어결과실행 시간메모리
762414Kaztaev_Alisher새로운 문제 (POI11_met)C++17
74 / 100
1060 ms27516 KiB
#include <bits/stdc++.h> #define ios ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0) #define file(s) if (fopen(s".in", "r")) freopen(s".in", "r", stdin), freopen(s".out", "w", stdout) #define all(a) a.begin() , a.end() #define F first #define S second #define int ll using namespace std; using ll = long long; const int N = 3e5+5 , inf = 2e9 + 7; const ll INF = 1e18 , mod = 1e9+7 , P = 6547; int p[N] , n , m , k ; int L[N] , R[N] , res[N]; int l[N] , r[N] , c[N]; ll t[N]; vector<int> g[N] , v; deque<pair<int,int>> q; void upd(int i, int x) { for(; i <= m; i |= (i + 1)) t[i] += x; } void updlr(int l, int r, int x){ upd(l, x); upd(r + 1, -x); } ll get(int i){ ll res = 0; for(; i > 0; i = (i & (i + 1)) - 1) res += t[i]; return res; } void cl(){ for(int i = 1; i <= m; i++) t[i] = 0; } void solve(){ cin >> n >> m; for(int i = 1; i <= m; i++) { int a; cin >> a; g[a].push_back(i); } for(int i = 1; i <= n; i++) cin >> p[i]; cin >> k; for(int i = 1; i <= n; i++) { L[i] = 1; R[i] = k; q.push_back(make_pair((k+1)/2,i)); } for(int i = 1; i <= k; i++) cin >> l[i] >> r[i] >> c[i]; for(int _ = 1; _ < 20; _++){ cl(); sort(all(q)); for(int i = 1; i <= k; i++){ if(l[i] > r[i]){ updlr(l[i],m,c[i]); updlr(1,r[i],c[i]); } else updlr(l[i],r[i],c[i]); while(!q.empty() && q.front().F == i){ int x = q.front().S; q.pop_front(); ll sum = p[x]; for(int j = 0 ; j < g[x].size(); j++) sum -= get(g[x][j]); if(sum <= 0){ res[x] = i; R[x] = i-1; } else { L[x] = i+1; } if(L[x] <= R[x]) q.push_back({(L[x]+R[x])/2,x}); } } } for(int i = 1; i <= n; i++) { if(res[i] == 0){ cout << "NIE\n"; } else { cout << res[i] << "\n"; } } } /* */ signed main(){ ios; solve(); return 0; }

컴파일 시 표준 에러 (stderr) 메시지

met.cpp: In function 'void solve()':
met.cpp:63:23: warning: comparison of integer expressions of different signedness: 'll' {aka 'long long int'} and 'std::vector<long long int>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
   63 |     for(int j = 0 ; j < g[x].size(); j++) sum -= get(g[x][j]);
      |                     ~~^~~~~~~~~~~~~
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