이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <string.h>
#include <vector>
#include <algorithm>
using namespace std;
#define MAXN 300005
typedef long long lld;
int N;
int R[MAXN],SA[MAXN],pos[MAXN],lcp[MAXN],P[MAXN][19],Q[MAXN][19];
lld ans;
char A[MAXN];
void Manachers()
{
int r = 0, p = 0;
for (int i=1;i<=N;i++){
if (i <= r) R[i] = min(R[2*p-i],r-i);
else R[i] = 0;
while (i > R[i] && A[i-R[i]-1] == A[i+R[i]+1]) R[i]++;
if (r < i+R[i]) r = i+R[i], p = i;
}
}
void SuffixArray()
{
int i,j,k;
int m = 27;
vector <int> cnt(max(N,m)+1,0),x(N+1,0),y(N+1,0);
for (i=1;i<=N;i++) cnt[x[i] = (A[i]=='#')?27:A[i]-'a'+1]++;
for (i=1;i<=m;i++) cnt[i] += cnt[i-1];
for (i=N;i;i--) SA[cnt[x[i]]--] = i;
for (int len=1,p=1;p<N;len<<=1,m=p){
for (p=0,i=N-len;++i<=N;) y[++p] = i;
for (i=1;i<=N;i++) if (SA[i] > len) y[++p] = SA[i]-len;
for (i=0;i<=m;i++) cnt[i] = 0;
for (i=1;i<=N;i++) cnt[x[y[i]]]++;
for (i=1;i<=m;i++) cnt[i] += cnt[i-1];
for (i=N;i;i--) SA[cnt[x[y[i]]]--] = y[i];
swap(x,y); p = 1; x[SA[1]] = 1;
for (i=1;i<N;i++)
x[SA[i+1]] = SA[i]+len <= N && SA[i+1]+len <= N && y[SA[i]] == y[SA[i+1]] && y[SA[i]+len] == y[SA[i+1]+len] ? p : ++p;
}
}
void LCP()
{
int i,j,k=0;
vector <int> rank(N+1,0);
for (i=1;i<=N;i++) rank[SA[i]] = i;
for (i=1;i<=N;lcp[rank[i++]]=k)
for (k?k--:0,j=SA[rank[i]-1];A[i+k]==A[j+k];k++);
for (i=2;i<=N;i++) P[i][0] = Q[i][0] = lcp[i];
for (i=2;i<=N;i++){
for (j=0;j<18;j++){
P[i][j+1] = (i+(1<<j)<=N?min(P[i][j],P[i+(1<<j)][j]):0);
Q[i][j+1] = (i-(1<<j)>0?min(Q[i][j],Q[i-(1<<j)][j]):0);
}
}
}
void proc(int a,int b)
{
int i;
int len=b-a+1, cnt=1;
a = pos[a];
int p=a+1, q=a;
for (i=19;i--;){
if (Q[q][i] >= len) q -= (1<<i), cnt += (1<<i);
if (P[p][i] >= len) p += (1<<i), cnt += (1<<i);
}
ans = max(ans,(lld)len*cnt);
}
int main()
{
int i,j;
scanf("%s",A+1); N = strlen(A+1);
SuffixArray(); LCP();
for (i=1;i<=N;i++) pos[SA[i]] = i;
for (i=1;i<=N;i++){
for (j=0;j<i&&i+j<=N&&A[i-j]==A[i+j];j++){
proc(i-j,i+j);
}
}
for (i=1;i<N;i++) if (A[i] == A[i+1]){
for (j=0;j<i&&i+j+1<=N&&A[i-j]==A[i+j+1];j++){
proc(i-j,i+j+1);
}
}
printf("%lld\n",ans);
/*for (i=N;i;i--) A[i+i-1] = A[i]; N = N+N-1;
for (i=2;i<N;i+=2) A[i] = '#';
Manachers();
for (i=1;i<=N;i++){
int l = i-R[i];
}*/
}
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