답안 #759693

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
759693 2023-06-16T15:17:54 Z doowey 보물 찾기 (CEOI13_treasure2) C++14
80 / 100
8 ms 996 KB
#include <bits/stdc++.h>
#include "treasure.h"

using namespace std;

typedef pair<int, int> pii;

#define fi first
#define se second
#define mp make_pair

map<pair<pii,pii>, int> Q;

int ask(int i0, int j0, int i1, int j1){
    if(i0 > i1 || j0 > j1) return 0;
    pair<pii, pii> rect = mp(mp(i0,j0), mp(i1,j1));
    if(Q.count(rect)){
        return Q[rect];
    }
    return Q[rect]=countTreasure(i0,j0,i1,j1);
}

int n;

int get_cost(int i0, int j0, int i1, int j1){
    if(i0 > i1 || j0 > j1) return 0;
    //if(Q.count(mp(mp(i0,j0), mp(i1,j1)))) return 0;
    return (i1 - i0 + 1) * (j1 - j0 + 1);
}

void findTreasure (int _n) {
    n = _n;
    int cost0;
    int cost1;
    int cost2;
    int cost3;
    int cur_value;
    vector<pii> ans;
    for(int i = 1; i <= n; i ++ ){
        for(int j = 1; j <= n; j ++ ){
            cost0 = get_cost(1, 1, i, j) + get_cost(1, 1, i - 1, j) + get_cost(1, 1, i, j - 1) + get_cost(1, 1, i - 1, j - 1);
            cost1 = get_cost(1, j, i, n) + get_cost(1, j, i - 1, n) + get_cost(1, j + 1, i, n) + get_cost(1, j + 1, i - 1, n);
            cost2 = get_cost(i, 1, n, j) + get_cost(i, 1, n, j - 1) + get_cost(i + 1, 1, n, j) + get_cost(i + 1, 1, n, j - 1);
            cost3 = get_cost(i, j, n, n) + get_cost(i + 1, j, n, n) + get_cost(i, j + 1, n, n) + get_cost(i + 1, j + 1, n, n);
            cur_value = 0;
            if(cost0 >= cost1 && cost0 >= cost2 && cost0 >= cost3){
                cur_value = ask(1, 1, i, j) - ask(1, 1, i - 1, j) - ask(1, 1, i, j - 1) + ask(1, 1, i - 1, j - 1);
            }
            else if(cost1 >= cost2 && cost1 >= cost3){
                cur_value = ask(1, j, i, n) - ask(1, j, i - 1, n) - ask(1, j + 1, i, n) + ask(1, j + 1, i - 1, n);
            }
            else if(cost2 >= cost3){
                cur_value = ask(i, 1, n, j) - ask(i, 1, n, j - 1) - ask(i + 1, 1, n, j) + ask(i + 1, 1, n, j - 1);
            }
            else{
                cur_value = ask(i, j, n, n) - ask(i + 1, j, n, n) - ask(i, j + 1, n, n) + ask(i + 1, j + 1, n, n);
            }
            if(cur_value == 1)
                ans.push_back(mp(i, j));
        }
    }
    for(auto x : ans) Report(x.fi, x.se);
}
# 결과 실행 시간 메모리 Grader output
1 Partially correct 1 ms 212 KB Output is partially correct - N = 5, K = 495, score = 8
2 Partially correct 1 ms 212 KB Output is partially correct - N = 10, K = 5821, score = 8
3 Partially correct 1 ms 304 KB Output is partially correct - N = 15, K = 26880, score = 8
4 Partially correct 1 ms 340 KB Output is partially correct - N = 16, K = 34273, score = 8
5 Partially correct 2 ms 468 KB Output is partially correct - N = 55, K = 4217920, score = 8
6 Partially correct 3 ms 596 KB Output is partially correct - N = 66, K = 8668573, score = 8
7 Partially correct 4 ms 724 KB Output is partially correct - N = 77, K = 15962895, score = 8
8 Partially correct 5 ms 816 KB Output is partially correct - N = 88, K = 27102241, score = 8
9 Partially correct 6 ms 980 KB Output is partially correct - N = 99, K = 43260000, score = 8
10 Partially correct 8 ms 996 KB Output is partially correct - N = 100, K = 45017701, score = 8