제출 #758825

#제출 시각아이디문제언어결과실행 시간메모리
758825Username4132구슬과 끈 (APIO14_beads)C++14
100 / 100
159 ms33432 KiB
#include<iostream> #include<algorithm> #include<vector> using namespace std; using pii = pair<int, int>; #define forn(i, n) for(int i=0; i<(int)n; ++i) #define PB push_back #define F first #define S second const int MAXN=200010, INF=2000000010; int n, dp[4][MAXN]; vector<pii> g[MAXN]; void dfs(int v, int p, int cost){ int sz = g[v].size() - (v!=0), cnt=0; vector<pii> d1(sz), d2(sz), d3(sz); for(pii to:g[v]) if(to.F!=p){ dfs(to.F, v, to.S); dp[1][v]+=dp[0][to.F]; d1[cnt]={to.S+dp[1][to.F]-dp[0][to.F], cnt}; d2[cnt]={to.S+dp[2][to.F]-dp[0][to.F], cnt}; d3[cnt]={dp[3][to.F]-dp[0][to.F], cnt}; cnt++; } sort(d1.begin(), d1.end(), greater<pii>()); sort(d2.begin(), d2.end(), greater<pii>()); sort(d3.begin(), d3.end(), greater<pii>()); dp[0][v]=(sz==0? 0 : max(d1[0].F + cost, 0))+dp[1][v]; dp[2][v]=dp[1][v]; if(sz>1){ int mx; if(d1[0].S!=d2[0].S) mx=d1[0].F+d2[0].F; else mx=max(d1[0].F+d2[1].F, d1[1].F+d2[0].F); if(mx>0) dp[2][v]=mx+dp[1][v]; } if(sz>0) dp[2][v]=max(dp[2][v], dp[1][v]+d3[0].F); if(sz>0) dp[3][v]=max(dp[3][v], dp[1][v]+d2[0].F+cost); dp[3][v]=max(dp[3][v], dp[2][v]); dp[3][v]=max(dp[3][v], dp[0][v]); } int main(){ scanf("%d", &n); forn(i, n-1){ int a, b, c; scanf("%d %d %d", &a, &b, &c); --a, --b; g[a].PB({b, c}), g[b].PB({a, c}); } dfs(0, 0, -INF); printf("%d\n", dp[3][0]); }

컴파일 시 표준 에러 (stderr) 메시지

beads.cpp: In function 'int main()':
beads.cpp:45:10: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   45 |     scanf("%d", &n);
      |     ~~~~~^~~~~~~~~~
beads.cpp:48:14: warning: ignoring return value of 'int scanf(const char*, ...)' declared with attribute 'warn_unused_result' [-Wunused-result]
   48 |         scanf("%d %d %d", &a, &b, &c); --a, --b;
      |         ~~~~~^~~~~~~~~~~~~~~~~~~~~~~~
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