이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <functional>
using namespace __gnu_pbds;
using namespace std;
typedef tree<int, null_type, less<int>, rb_tree_tag,
tree_order_statistics_node_update>
ordered_set;
//set.find_by_order(x) x-position value
//set.order_of_key(x) number of strictly less elements don't need *set.??
#define N 100005
#define wr cout << "Continue debugging\n";
#define all(x) (x).begin(), (x).end()
#define ll long long int
#define pii pair <double, int>
#define pb push_back
#define ff first
#define ss second
vector<pii> E[N];
double F(int x){
double res = 1.0;
while(x--) res *= 2;
return res;
}
void dfs(int nd, int h, vector<int> arr, vector<int> &z, vector<double> &dis, vector<bool> &vis){
if (!arr[nd]){
z.pb(nd);
dis[nd] = 0;
}
vis[nd] = 1;
for (auto i : E[nd]){
if (vis[i.ff] or i.ff == h) continue;
dfs(i.ff, h, arr, z, dis, vis);
}
}
double solve(int n, int m, int k, int h, vector<int> x, vector<int> y, vector<int> c, vector<int> arr){
for (int i = 0; i < n; i++) E[i].clear();
for (int i = 0; i < m; i++){
E[x[i]].pb({y[i], c[i]});
E[y[i]].pb({x[i], c[i]});
}
vector<int> vec, z = {0};
vector<bool> vis(n, 0);
vector<double> dis(n, 1e15);
dis[0] = 0;
dfs(0, h, arr, z, dis, vis);
for (int i = 0; i < n; i++){
if (arr[i] == 2) vec.pb(i);
}
set<pii> q;
for (auto i : z) q.insert({0, i});
for (int i = 0; i <= k; i++){
while(!q.empty()){
int x = (*q.begin()).ss;
q.erase(q.begin());
if (x == h) continue;
for (auto j : E[x]){
double res = (dis[x]/F(i))+j.ss;
if (dis[j.ff] > res){
q.erase({dis[j.ff], j.ff});
dis[j.ff] = res;
q.insert({dis[j.ff], j.ff});
}
}
}
for (auto j : z) q.insert({0, j});
for (auto j : vec) q.insert({dis[j], j});
}
if (dis[h] == 1e15) return double(-1);
return dis[h];
}
// int main ()
// {
// int n, m, k, h;
// cin >> n >> m >> k >> h;
// vector<int> x(m), y(m), c(m), arr(n);
// for (int i = 0; i < m; i++){
// cin >> x[i] >> y[i] >> c[i];
// }
// for (int i = 0; i < n; i++) cin >> arr[i];
// cout << solve(n,m,k,h,x,y,c,arr);
// }
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