제출 #755311

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
755311		Red_Inside	죄수들의 도전 (IOI22_prison)	C++17	100 / 100	14 ms	1016 KiB

prison

#include "prison.h"
#include <bits/stdc++.h>

//#pragma GCC optimize("O1,O2,O3,Ofast,unroll-loops")

#define ll long long
#define f first
#define s second
#define pb push_back
#define mp make_pair
#define o cout<<"BUG"<<endl;
#define FOR(i, j, n) for(int j = i; j < n; ++j)
#define forn(i, j, n) for(int j = i; j <= n; ++j)
#define nfor(i, j, n) for(int j = n; j >= i; --j)
#define all(v) v.begin(), v.end()
#define ld long double
#define ull unsigned long long
 
using namespace std;
const int maxn=2e5+10,LOG=17,mod=1e9+7;
int block = 650, timer = 0;
const double eps = 1e-9;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define IOS ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);
 
#define bt(i) (1 << (i))
//#define int ll
const long long inf=2e18;
#define y1 yy
#define pii pair <int, int>

int etot(int x)
{
	return (x == 0 ? -1 : -2);
}

int oppo(int x)
{
	return (x == 0 ? -2 : -1);
}

pii seg(int x, int n)
{
	int l = 1;
	int r = 5000;
	forn(1, i, n)
	{
		l++;
		r--;
		int m1 = l + (r - l) / 3;
		int m2 = l + 2*(r - l) / 3;
		if(x <= m1)
		{
			r = m1;
		}
		else
		if(m1 < x && x <= m2)
		{
			l = m1+1;
			r = m2;
		}
		else
		{
			l = m2+1;
		}
	}
	return {l, r};
}

int to(int x, int n)
{
	int l = 1;
	int r = 5000;
	int last = 0;
	forn(1, i, n)
	{
		l++;
		r--;
		int m1 = l + (r - l) / 3;
		int m2 = l + 2*(r - l) / 3;
		if(x <= m1)
		{
			last = 0;
			r = m1;
		}
		else
		if(m1 < x && x <= m2)
		{
			last = 1;
			l = m1+1;
			r = m2;
		}
		else
		{
			last = 2;
			l = m2+1;
		}
	}
	return last;
}

vector <vector <int> > devise_strategy(int n)
{
	vector <vector <int> > turn(21);
	forn(0, i, 20)
	{
		turn[i].assign(n+1, 0);
	}
	turn[0][0] = 0;
	forn(1, x, n)
	{
		if(x == 1)
			turn[0][x] = -1;
		else
		if(x == 5000)
			turn[0][x] = -2;
		else
			turn[0][x] = 1+to(x, 1);
	}
	forn(1, i, 18)
	{
		int iter = (i - 1) / 3+1;
		turn[i][0] = (iter % 2 == 1 ? 1 : 0);
		forn(1, x, n)
		{
			pii ret = seg(x, iter);
			int l = ret.f;
			int r = ret.s;
			int was = to(x, iter);
//			if(i == 1 && x == 189) cout << was << " " << l << " " << r << " " << iter << endl;
			int poin = (i - 1) % 3;
			if(was < poin)
			{
				turn[i][x] = etot(turn[i][0]);
				continue;
			}
			if(poin < was)
			{
				turn[i][x] = oppo(turn[i][0]);
				continue;
			}
			if(x <= l)
			{
				turn[i][x] = etot(turn[i][0]);
				continue;
			}
			if(r <= x)
			{
				turn[i][x] = oppo(turn[i][0]);
				continue;
			}
			if(iter == 6)
			{
				l++;
				r--;
				int mid = (l + r) / 2;
				if(x <= mid)
				{
					turn[i][x] = 19;
				}
				else
				{
					turn[i][x] = 20;
				}
				continue;
			}
			int kuda = to(x, iter+1);
//			if(i == 1 && x == 189)
//				cout << " KUDA " << kuda << endl;
			turn[i][x] = iter*3+1+kuda;
		}
	}
	turn[19][0] = (turn[18][0]^1);
	turn[20][0] = turn[19][0];
	forn(1, x, n)
	{
		pii ret = seg(x, 6);
		int l = ret.f + 1;
		int r = ret.s - 1;
		int mid = (l + r) / 2;
		if(x <= l)
		{
			turn[19][x] = etot(turn[19][0]);
		}
		else
		{
			turn[19][x] = oppo(turn[19][0]);
		}
		if(x <= mid+1)
		{
			turn[20][x] = etot(turn[20][0]);
		}
		else
		{
			turn[20][x] = oppo(turn[20][0]);
		}
	}
	return turn;
}

• Subtask 1: 5 / 5
• Subtask 2: 5 / 5
• Subtask 3: 90 / 90