이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#pragma GCC optimize("O1")
//#define int long long
#define ll long long
#define fi first
#define se second
#define pb push_back
using namespace std;
typedef pair<int,int> pii;
typedef pair<int,pii> ipii;
const int MAXN = 3e5+10;
struct node{//segtree RMQ
int val = 0; int l, r;
node *le, *ri;
void bd(int l2, int r2){
l = l2; r = r2;
if(l==r) return;
}
int que(int x, int y){
if(x<=l && r<=y) return val;
if(r<x || y<l) return 0;
if(le == NULL){
le = new node(); le->bd(l, (l+r)/2);
}
if(ri == NULL){
ri = new node(); ri->bd((l+r)/2+1, r);
}
return max(le->que(x, y), ri->que(x, y));
}
node *upd(int x, int p){
if(r<x || x<l) return this;
if(le == NULL){
le = new node(); le->bd(l, (l+r)/2);
}
if(ri == NULL){
ri = new node(); ri->bd((l+r)/2+1, r);
}
//mengandung x
node *ret; ret = new node();
*ret = *this;
if(l==r){
ret->val = p;
return ret;
}
ret->le = ret->le->upd(x, p);
ret->ri = ret->ri->upd(x, p);
ret->val = max(ret->le->val, ret->ri->val);
return ret;
}
};
node *A[MAXN];
int n, subtask;
int t[MAXN];
signed main(){
ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);
cin >> n >> subtask;
A[0] = new node();
A[0]->bd(0, MAXN-10);
for(int i=1; i<=n; i++){
A[i] = new node();
cin >> t[i];
if(t[i] > 0){
*A[i] = *A[i-1];
A[i] = A[i]->upd(0, i);
//cout << i-1 << ' ' << A[i-1]->que(0, 0) << "que\n";
} else {
int idx = A[i-1]->que(0, (-t[i])-1);
*A[i] = *A[idx-1];
A[i] = A[i]->upd((-t[i]), i);
}
cout << t[A[i]->que(0, 0)] << '\n';
//cout << t[A[i]->que(0, 0)] << ' ' << A[i]->que(0, 0) <<'p'<< '\n';
/*for(int j=i; j>=1; j--){
cout << A[j]->que(0, 0) << ' ' << j << '\n';
}*/
}
}
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