답안 #754012

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
754012 2023-06-06T13:24:45 Z Zflop 비밀 (JOI14_secret) C++14
컴파일 오류
0 ms 0 KB
const int NMAX = (int)1e3;
int n;
int prec[NMAX][NMAX];
void DC	(int l,int r,int A[]){
	if(l >= r) return;
	int m = (l + r) / 2;
	prec[m][m] = A[m];
	prec[m + 1][m + 1] = A[m + 1];
	for (int i = m - 1; i >= l;--i) prec[i][m] = Secret(prec[i + 1][m],A[i]);
	for (int i = m + 2; i <= r;++i) prec[m][i] = Secret(prec[m + 1][i - 1],A[i]);
	DC(l,m);
	DC(m + 1,r);
	}
void init(int N,int A[]){
	n = N;
	DC(0,N - 1);
}
int Query(int L,int R){
	int l = 0,r = n - 1;
	while(true){
		int m = (l + r) / 2;
		if(L <= m && m < R) return Secret(prec[L][m],prec[m + 1],R); 
		if(R < m) r = m;
		else l = m;
		}
	}

Compilation message

secret.cpp: In function 'void DC(int, int, int*)':
secret.cpp:9:47: error: 'Secret' was not declared in this scope
    9 |  for (int i = m - 1; i >= l;--i) prec[i][m] = Secret(prec[i + 1][m],A[i]);
      |                                               ^~~~~~
secret.cpp:10:47: error: 'Secret' was not declared in this scope
   10 |  for (int i = m + 2; i <= r;++i) prec[m][i] = Secret(prec[m + 1][i - 1],A[i]);
      |                                               ^~~~~~
secret.cpp:11:8: error: too few arguments to function 'void DC(int, int, int*)'
   11 |  DC(l,m);
      |        ^
secret.cpp:4:6: note: declared here
    4 | void DC (int l,int r,int A[]){
      |      ^~
secret.cpp:12:12: error: too few arguments to function 'void DC(int, int, int*)'
   12 |  DC(m + 1,r);
      |            ^
secret.cpp:4:6: note: declared here
    4 | void DC (int l,int r,int A[]){
      |      ^~
secret.cpp: In function 'void init(int, int*)':
secret.cpp:16:12: error: too few arguments to function 'void DC(int, int, int*)'
   16 |  DC(0,N - 1);
      |            ^
secret.cpp:4:6: note: declared here
    4 | void DC (int l,int r,int A[]){
      |      ^~
secret.cpp: In function 'int Query(int, int)':
secret.cpp:22:30: error: 'Secret' was not declared in this scope
   22 |   if(L <= m && m < R) return Secret(prec[L][m],prec[m + 1],R);
      |                              ^~~~~~