답안 #753696

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
753696 2023-06-05T17:38:33 Z epicci23 Alternating Heights (CCO22_day1problem1) C++17
0 / 25
610 ms 12764 KB
#include "bits/stdc++.h"
#pragma optimize ("Bismillahirrahmanirrahim")
using namespace std;
#define pb push_back
#define ff first
#define ss second
#define endl "\n" 
#define int long long
#define double long double
#define sz(x) ((int)(x).size())
#define all(x) (x).begin(), (x).end()
#define rall(x) (x).rbegin(), (x).rend()
#define what_is(x) cerr << #x << " is " << x << endl;
//#define m (l+r)/2
constexpr int N=200005;
constexpr int MOD=1000000007;
constexpr int  INF2 = LLONG_MAX;
constexpr int INF=(int)1e18;
constexpr int LOG=30;
typedef pair<int,int> pii;
typedef tuple<int,int,int> tp;
typedef priority_queue<pii,vector<pii>,greater<pii>> min_pq;
typedef priority_queue<pii> max_pq;
typedef long long ll;
//to think//
/*
 * graph approach
 * dp
 * dividing the problem to smaller statements
 * finding the real constraint
 * sqrt decomposition
 * greedy approach
 * pigeonhole principle
 * rewriting the problem/equality 
 * bitwise approaches
 * binary search if monotonic
 * divide and conquer
 * combinatorics
 * inclusion - exclusion
 * think like bfs
*/



inline int in()
{
  int x;cin >> x;
  return x;
}

inline string in2()
{
  string x;cin >> x;
  return x;
}


vector<int> v[3003];
int col[3003];
bool ok=0;

void dfs(int c)
{
  if(ok) return;
  if(col[c]==1) {ok=1;return;}
  if(col[c]==2) return;
  col[c]=1;
  for(int x:v[c]) dfs(x);
  col[c]=2;
}

void solve()
{
  int n=in(),k=in(),q=in();
  int ar[n+1];
  for(int i=1;i<=n;i++) ar[i]=in();
  
  int xd[n+1];

  for(int i=1;i<=n;i++)
  {
    int l=i,r=n;
    while(l<r)
    {
      int mid=(l+r)/2;
      ok=0;
      for(int j=1;j<=k;j++) col[j]=0;
      for(int j=1;j<=k;j++) v[j].clear();
      for(int j=i;j<mid;j++)
      {
        if((j-i)&1) v[ar[j+1]].pb(ar[j]);
        else v[ar[j]].pb(ar[j+1]);
      }
      for(int j=1;j<=k;j++) dfs(j);
      if(ok) r=mid;
      else l=mid+1;
    }
    xd[i]=l;
  }

  for(int i=1;i<=q;i++)
  {
    int u=in(),v=in();
    if(xd[u]<=v) cout << "NO\n";
    else cout << "YES\n";
  }
}

int32_t main(){
   

     cin.tie(0); ios::sync_with_stdio(0);
     cout << fixed <<  setprecision(15);
   
   int t=1;//cin>> t;
 
 for(int i=1;i<=t;i++)
 {
  //  cout << "Case #" << i << ": ";
    solve();
 }
 
 return 0;
}

Compilation message

Main.cpp:2: warning: ignoring '#pragma optimize ' [-Wunknown-pragmas]
    2 | #pragma optimize ("Bismillahirrahmanirrahim")
      |
# 결과 실행 시간 메모리 Grader output
1 Correct 192 ms 12760 KB Output is correct
2 Incorrect 201 ms 12764 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Incorrect 147 ms 11044 KB Output isn't correct
2 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 1 ms 340 KB Output is correct
2 Incorrect 610 ms 540 KB Output isn't correct
3 Halted 0 ms 0 KB -
# 결과 실행 시간 메모리 Grader output
1 Correct 192 ms 12760 KB Output is correct
2 Incorrect 201 ms 12764 KB Output isn't correct
3 Halted 0 ms 0 KB -