Submission #753542

#	Time	Username	Problem	Language	Result	Execution time	Memory
753542		Ronin13	Potemkin cycle (CEOI15_indcyc)	C++14	30 / 100	526 ms	1048576 KiB

indcyc

#include <bits/stdc++.h>
#define ll long long
#define f first
#define s second
#define pll pair<ll,ll>
#define pb push_back
#define epb emplace_back
#define ull unsigned ll
#define pii pair<int,int>
using namespace std;

const int nmax  = 1001;
int mask[nmax];

int main(){
    //ios_base::sync_with_stdio(false); cin.tie(0);
    int n, m; cin >> n >> m;
    for(int i = 1; i <= m; i++){
        int u, v; cin >> u >> v;
        u--;
        v--;
        mask[u] |= (1 << v);
        mask[v] |= (1 << u);
    }
    for(int s = 0; s < n; s++){
        int dp[(1 << n)][n];
        for(int j = 0; j < (1 << n); j++){
            for(int k = 0; k < n; k++)
                dp[j][k] = -1;
        }
        dp[(1 << s)][s] = 0;
        pii ans = {-1, -1};
        for(int i = (1 << s) + 1; i < (1 << n); i++){
            if(!(i & (1 << s))) continue;
            for(int j = 0; j < n; j++){
                if(j == s) continue;
                if((1 << j) & i){
                    int m = mask[j] & (i ^ (1 << j));
                    int m1 = m & (i ^ (1 << s));
                    if(!m) continue;

                    if(m1  && __builtin_popcount(m1) > 1) continue;
                    if(!m1){
                        if(__builtin_popcount(i) == 2)
                            dp[i][j] = s;
                    }
                    if(m1){
                        int o = log2(m1);
                        if(dp[i ^ (1 << j)][o] != -1){
                            if(!(mask[j] & (1 << s)))dp[i][j] = o;
                            if(__builtin_popcount(i) < 4) continue;
                            if((mask[j] & (1 << s)) && ans.f == -1) ans = {i, j}, dp[i][j] = o;
                        }
                    }
                }
            }
        }

        if(ans.f == -1) continue;

        while(ans.s != s){
            cout << ans.s + 1<< ' ';
            ans.f ^= (1 << ans.s);
            ans.s = dp[ans.f ^ (1 << ans.s)][ans.s];
        }
        cout << s + 1;
        return 0;
    }
    cout << "no\n";
}

• Subtask 1: 10 / 10
• Subtask 2: 10 / 10
• Subtask 3: 10 / 10
• Subtask 4: 0 / 10
• Subtask 5: 0 / 10
• Subtask 6: 0 / 10
• Subtask 7: 0 / 10
• Subtask 8: 0 / 10
• Subtask 9: 0 / 10
• Subtask 10: 0 / 10