Submission #753519

#	Time	Username	Problem	Language	Result	Execution time	Memory
753519		Fidan	K blocks (IZhO14_blocks)	C++17	0 / 100	1 ms	468 KiB

blocks

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
#define rep(i, a, b) for(ll i=ll(a); i<ll(b); i++)
#define repn(i, a, b) for(ll i=ll(b)-1; i>=ll(a); i--)
#define ff first
#define ss second
#define si size()
#define pb push_back
#define be begin()
#define en end()
const ll N=110;
const ll K=110;
const ll inf=(1e9);
vector<vector<ll>> dp(N, vector<ll> (K, -1));
vector<vector<ll>> mx(N, vector<ll> (N));
vector<ll> pre(N);
vector<ll> a(N);
ll sol(ll n, ll k){
	if(n<k) return -1;
	if(k==1) return mx[1][k];
	if(k==n) return pre[k];
	if(dp[n][k]!=-1){
		return dp[n][k];
	}
	rep(i, 0, n){
		ll x=sol(i, k-1);
		if(x!=-1){
			if(dp[n][k]==-1) dp[n][k]=x+mx[i+1][n];
			else dp[n][k]=min(dp[n][k], x+mx[i+1][n]);
		}
	}
	return dp[n][k];
}
void solve(){
	ll n, k;
	cin>>n>>k;
	rep(i, 1, n+1){
		cin>>a[i];
	}
	rep(i, 1, n+1){
		mx[i][i]=a[i];
		rep(j, i+1, n+1){
			mx[i][j]=max(a[j], mx[i][j-1]);
		}
	}
	rep(i, 1, n+1){
		pre[i]=pre[i-1]+a[i];
	}
	cout<<sol(n, k);
}
int main(){
	ios_base::sync_with_stdio(0);
	cin.tie(0);
	ll t=1;
	//~ cin>>t;
	while(t--){
		solve();
	}
	return 0;
}

• Subtask 1: 0 / 14
• Subtask 2: 0 / 18
• Subtask 3: 0 / 21
• Subtask 4: 0 / 47