이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "sequence.h"
#include <bits/stdc++.h>
#define SZ(s) ((int) ((s).size()))
using namespace std;
vector<int> medians(const vector<int> values) {
int n = SZ(values);
assert(n > 0);
if (n % 2 == 0) {
return {values[n/2 - 1], values[n / 2]};
} else {
return {values[n/2]};
}
}
int sub1(const vector<int>& a) {
int n = SZ(a);
int res = 0;
for (int l = 0; l < n; ++l) {
for (int r = l; r < n; ++r) {
vector<int> b(a.begin() + l, a.begin() + r + 1);
unordered_map<int, int> cnt;
for (int val : b) cnt[val] += 1;
sort(b.begin(), b.end());
auto meds = medians(b);
for (int med : meds) {
res = max(res, cnt[med]);
}
}
}
return res;
}
#include <ext/pb_ds/assoc_container.hpp> // Common file
#include <ext/pb_ds/tree_policy.hpp> // Including tree_order_statistics_node_update
using namespace __gnu_pbds;
typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_set;
using namespace __gnu_pbds;
int sub2(const vector<int>& a) {
int n = SZ(a);
int res = 0;
for (int l = 0; l < n; ++l) {
unordered_map<int, int> cnt;
ordered_set values;
for (int r = l; r < n; ++r) {
cnt[a[r]]++;
values.insert(a[r]);
int k = SZ(values);
if (k % 2 == 0) {
res = max(res, cnt[*values.find_by_order(k / 2 - 1)]);
res = max(res, cnt[*values.find_by_order(k / 2)]);
} else {
res = max(res, cnt[*values.find_by_order(k / 2)]);
}
}
}
return res;
}
bool is_sub_3(const std::vector<int> a) {
auto mit = max_element(a.begin(), a.end());
return std::is_sorted(a.begin(), mit)
&& std::is_sorted(mit, a.end(), std::greater<int>());
}
int len(const std::pair<int,int>& p) {
return p.second - p.first + 1;
}
int sub3(const vector<int>& a) {
int n = SZ(a);
unordered_map<int, vector<pair<int,int>>> pos;
int l = 0;
while (l < n) {
int r = l;
while (r < n && a[l] == a[r]) ++r;
pos[a[l]].emplace_back(l, r-1);
l = r;
}
int res = 0;
for (const auto& [val, lrs] : pos) {
// only 1 segment
for (const auto& lr : lrs) res = max(res, len(lr));
// 2 segments
if (SZ(lrs) < 2) continue;
assert(SZ(lrs) == 2);
int cnt_equal = len(lrs[0]) + len(lrs[1]);
int cnt_all = len({lrs[0].first, lrs[1].second});
if (cnt_equal*2 > cnt_all) res = max(res, cnt_equal);
}
return res;
}
int sequence(int n, std::vector<int> a) {
if (is_sub_3(a)) return sub3(a);
if (n <= 2000) return sub2(a);
return 0;
}
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