Submission #752317

#TimeUsernameProblemLanguageResultExecution timeMemory
752317gnuDijamant (COCI22_dijamant)C++14
70 / 70
226 ms104896 KiB
#include <iostream> #include <vector> using namespace std; vector<vector<long long>> pref; long long get(int i, int l, int r) { return pref[i][r+1] - pref[i][l]; } int main() { int n, m; cin >> n >> m; vector<string> mat(n); for (auto& x : mat) cin >> x; vector<vector<int>> a, b, c, d; a = b = c = d = vector<vector<int>>(n, vector<int>(m, -1)); pref = vector<vector<long long>>(n, vector<long long>(m + 1)); for (int i = 0; i < n; ++i) { for (int j = 1; j <= m; ++j) { pref[i][j] = pref[i][j - 1] + (mat[i][j - 1] == '#'); } } //cout << get(2, 1, 6) << '\n'; for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { if (i > 0 && j + 2 < m) { if (mat[i][j] == '#' && mat[i][j + 1] == '.' && mat[i][j + 2] == '#' && mat[i - 1][j + 1] == '#') a[i][j] = 1, b[i][j + 2] = 1; } } } for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { if (mat[i][j] != '#') continue; int x1 = j; ++j; for (; j < m; ++j) { if (mat[i][j] == '#') break; } //cout << i << ' ' << j << '\n'; if (j == m || i == 0 || x1 + 1 >= m || j==0) continue; if (a[i - 1][x1 + 1] == 1 && b[i - 1][j - 1] == 1 && get(i-1, x1+1, j-1) == 2) a[i][x1] = 1, b[i][j] = 1; --j; } } for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { if (i + 1 < n && j + 2 < m) { if (mat[i][j] == '#' && mat[i][j + 1] == '.' && mat[i][j + 2] == '#' && mat[i + 1][j + 1] == '#') c[i][j] = 1, d[i][j + 2] = 1; } } } for (int i = n-1; i > 0; --i) { for (int j = 0; j < m; ++j) { if (mat[i][j] != '#') continue; int x1 = j; ++j; for (; j < m; ++j) { if (mat[i][j] == '#') break; } if (j == m || i == n-1 || x1 + 1 >= m || j == 0) continue; if (c[i + 1][x1 + 1] == 1 && d[i + 1][j - 1] == 1 && get(i+1, x1+1, j-1) == 2) c[i][x1] = 1, d[i][j] = 1; --j; } } int ans = 0; for (int i = 0; i < n; ++i) { for (int j = 0; j < m; ++j) { if (mat[i][j] != '#') continue; int x1 = j; ++j; for (; j < m; ++j) { if (mat[i][j] == '#') break; } if (j == m) continue; if (a[i][x1] == 1 && b[i][j] == 1 && c[i][x1] == 1 && d[i][j] == 1) ++ans; --j; } } cout << ans << '\n'; return 0; }
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