Submission #751799

#TimeUsernameProblemLanguageResultExecution timeMemory
751799owoovoCollecting Stamps 3 (JOI20_ho_t3)C++14
5 / 100
95 ms108228 KiB
#include<bits/stdc++.h>
#define ll long long
using namespace std;
const ll maxn=1e15;
ll n,l,dpl[210][210][210],dpr[210][210][210],x[210],t[210];
ll dis(int a,int b){
    if(a<b)swap(a,b);
    return min(x[a]-x[b],x[b]-x[a]+l);
}
int main(){
    ios::sync_with_stdio(0);
    cin.tie(0);
    int ans=0;
    cin>>n>>l;
    for(int i=1;i<=n;i++)cin>>x[i];
    x[n+1]=l;
    for(int i=1;i<=n;i++)cin>>t[i];
    for(int i=0;i<=n;i++){
        for(int j=0;j<=n;j++){
            for(int k=0;k<=n+1;k++){
                dpl[i][j][k]=maxn;
                dpr[i][j][k]=maxn;
            }
        }
    }
    for(int i=0;i<=n;i++){
        dpl[0][i][0]=0;
        dpr[i][0][0]=0;
    }
    for(int i=1;i<=n;i++){
        for(int j=0;j<=i;j++){
            for(int k=i;k>=0;k--){
                dpl[j][i-j][k]=dpl[j][i-j][k+1];
                dpr[j][i-j][k]=dpr[j][i-j][k+1];
                if(j>0){
                    dpl[j][i-j][k]=min(dpl[j][i-j][k],min(dpr[j-1][i-j][k]+dis(n+1-(j),i-j),dpl[j-1][i-j][k]+dis(n+1-(j-1),n+1-(j))));
                    if(k>0&&(dpl[j-1][i-j][k-1]+dis(n+1-(j-1),n+1-j))<=t[n+1-j])dpl[j][i-j][k]=min(dpl[i][i-j][k],dpl[j-1][i-j][k-1]+dis(n+1-(j-1),n+1-j));
                    if(k>0&&(dpr[j-1][i-j][k-1]+dis(i-j,n+1-j))<=t[n+1-j])dpl[j][i-j][k]=min(dpl[i][i-j][k],dpr[j-1][i-j][k-1]+dis(i-j,n+1-j));
                }
                if(i-j>0){
                    dpr[j][i-j][k]=min(dpr[j][i-j][k],min(dpr[j][i-j-1][k]+dis(i-j-1,i-j),dpl[j][i-j-1][k]+dis(i-j,n+1-(j))));
                    if(k>0&&(dpr[j][i-j-1][k-1]+dis(i-j,i-j-1))<=t[i-j])dpr[j][i-j][k]=min(dpr[i][i-j][k],dpr[j][i-j-1][k-1]+dis(i-j,i-j-1));
                    if(k>0&&(dpl[j][i-j-1][k-1]+dis(i-j,n+1-j))<=t[i-j])dpr[j][i-j][k]=min(dpr[i][i-j][k],dpl[j][i-j-1][k-1]+dis(i-j,n+1-j));
                }
            }
        }
    }
    for(int i=1;i<=n;i++){
        for(int j=0;j<=i;j++){
            for(int k=0;k<=i;k++){
                if(dpl[j][i-j][k]<maxn||dpr[j][i-j][k]<maxn){
                    ans=max(ans,k);
                }
            }
        }
    }
    cout<<ans<<"\n";
    return 0;
}
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