제출 #751075

#제출 시각아이디문제언어결과실행 시간메모리
751075alex_2008게임 (IOI13_game)C++14
27 / 100
771 ms25936 KiB
#include "game.h"
#include <vector>
typedef long long ll;
using namespace std;
const int N = 2023, M = 2023;
ll TTree[11][400400], tree[N][4 * M], tree2[N][4 * M], tree3[N][4 * M];
int block = 46;
int H, W;
ll __gcd(ll a, ll b) {
	while (a && b) {
		(a > b) ? a %= b : b %= a;
	}
	return a + b;
}
void Upd(int R, int C, ll value, int v, int tl, int tr) {
	if (tl > C || tr < C) {
		return;
	}
	if (tl == tr) {
		TTree[R][v] = value;
		return;
	}
	int tm = (tl + tr) / 2;
	Upd(R, C, value, 2 * v, tl, tm);
	Upd(R, C, value, 2 * v + 1, tm + 1, tr);
	TTree[R][v] = __gcd(TTree[R][2 * v], TTree[R][2 * v + 1]);
}
ll _GCD_(int R, int v, int tl, int tr, int l, int r) {
	if (tl >= l && tr <= r) return TTree[R][v];
	if (tl > r || tr < l) return 0;
	int tm = (tl + tr) / 2;
	return __gcd(_GCD_(R, 2 * v, tl, tm, l, r),
		_GCD_(R, 2 * v + 1, tm + 1, tr, l, r));
}
void update1(int R, int C, ll value, int v, int tl, int tr) {
	if (tl > C || tr < C) {
		return;
	}
	if (tl == tr) {
		tree[R][v] = value;
		return;
	}
	int tm = (tl + tr) / 2;
	update1(R, C, value, 2 * v, tl, tm);
	update1(R, C, value, 2 * v + 1, tm + 1, tr);
	tree[R][v] = __gcd(tree[R][2 * v], tree[R][2 * v + 1]);
}
ll GCD(int R, int v, int tl, int tr, int l, int r) {
	if (tl >= l && tr <= r) return tree[R][v];
	if (tl > r || tr < l) return 0;
	int tm = (tl + tr) / 2;
	return __gcd(GCD(R, 2 * v, tl, tm, l, r),
		GCD(R, 2 * v + 1, tm + 1, tr, l, r));
}
void update2(int R, int C, ll value, int v, int tl, int tr) {
	if (tl > R || tr < R) {
		return;
	}
	if (tl == tr) {
		tree2[C][v] = value;
		return;
	}
	int tm = (tl + tr) / 2;
	update2(R, C, value, 2 * v, tl, tm);
	update2(R, C, value, 2 * v + 1, tm + 1, tr);
	tree2[C][v] = __gcd(tree2[C][2 * v], tree2[C][2 * v + 1]);
}
ll GCD2(int C, int v, int tl, int tr, int l, int r) {
	if (tl >= l && tr <= r) return tree2[C][v];
	if (tl > r || tr < l) return 0;
	int tm = (tl + tr) / 2;
	return __gcd(GCD2(C, 2 * v, tl, tm, l, r),
		GCD2(C, 2 * v + 1, tm + 1, tr, l, r));
}
void update3(int R, int C, ll value, int v, int tl, int tr) {
	if (tl > C || tr < C) {
		return;
	}
	if (tl == tr) {
		tree3[R][v] = value;
		return;
	}
	int tm = (tl + tr) / 2;
	update3(R, C, value, 2 * v, tl, tm);
	update3(R, C, value, 2 * v + 1, tm + 1, tr);
	tree3[R][v] = __gcd(tree3[R][2 * v], tree3[R][2 * v + 1]);
}
ll GCD3(int R, int v, int tl, int tr, int l, int r) {
	if (tl >= l && tr <= r) return tree3[R][v];
	if (tl > r || tr < l) return 0;
	int tm = (tl + tr) / 2;
	return __gcd(GCD3(R, 2 * v, tl, tm, l, r),
		GCD3(R, 2 * v + 1, tm + 1, tr, l, r));
}
void init(int R, int C) {
	H = R;
	W = C;
}
void update(int R, int Q, ll K) {
	Upd(R, Q, K, 1, 0, W - 1);
	if (H > 10) {
		update1(R, Q, K, 1, 0, W - 1);
		update2(R, Q, K, 1, 0, H - 1);
		for (int i = max(0, R - block + 1); i <= min(R, H - block); i++) {
			update3(i, Q, GCD2(Q, 1, 0, H - 1, i, i + block - 1), 1, 0, W - 1);
		}
	}
}
ll calculate(int P, int Q, int U, int V) {
	ll u = 0;
	if (H > 10) {
		int i;
		for (i = P; i + block - 1 <= U; i += block) {
			u = __gcd(u, GCD3(i, 1, 0, W - 1, Q, V));
		}
		for (; i <= U; i++) {
			u = __gcd(u, GCD(i, 1, 0, W - 1, Q, V));
		}
	}
	else {
		for (int i = P; i <= U; i++) {
			u = __gcd(u, _GCD_(i, 1, 0, W - 1, Q, V));
		}
	}
	return u;
}
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