이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// header file
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
// pragma
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
// macros
#define endl "\n"
#define ll long long
#define mp make_pair
#define ins insert
#define lb lower_bound
#define pb push_back
#define ub upper_bound
#define lll __int128
#define fi first
#define se second
using namespace std;
using namespace __gnu_pbds;
typedef tree<int, null_type, less_equal<int>, rb_tree_tag, tree_order_statistics_node_update> ordered_multiset;
typedef tree<int, null_type, less<int>, rb_tree_tag,tree_order_statistics_node_update> ordered_set;
string operate(string a, string b) {
for(int it = 0; it < a.size(); ++it) {
if(a[it] == b[it])
continue;
bool j = 0, o = 0, i = 0;
if(a[it] == 'J')
j = 1;
else if(a[it] == 'O')
o = 1;
else
i = 1;
if(b[it] == 'J')
j = 1;
else if(b[it] == 'O')
o = 1;
else
i = 1;
if(!j)
a[it] = 'J';
else if(!o)
a[it] = 'O';
else
a[it] = 'I';
}
return a;
}
int to_num(string s) {
if(s == "J")
return 0;
else if(s == "O")
return 1;
else
return 2;
}
int to_num(char x) {
if(x == 'J')
return 0;
else if(x == 'O')
return 1;
else
return 2;
}
const int lim = 2e5 + 5;
struct fenwick {
int a[lim];
fenwick() {
memset(a, 0, sizeof(a));
}
void update(int idx, int val) {
while(idx < lim) {
a[idx] += val;
idx += (idx&-idx);
}
}
int query(int idx) {
int res = 0;
while(idx > 0) {
res += a[idx];
idx -= (idx&-idx);
}
return res;
}
int query(int l, int r) {
return query(r) - query(l - 1);
}
};
// buat bit 27 state 1 nya implicit disimpan di segment bawahnya
// remove segment bawahnya per segment gtu
// nanti cnt cari mutually exclusive segment
// char akhirnya berapa
// char 1, 2, 3, dan akhir
// 4 pertama -> quadruplet 1
// 4 kedua -> quadruplet 2
bool compatible[3][3][3][3][3][3][3][3];
bool possible[3][3][3][3];
int pref[lim][3][3][3];
int cnt[3][3][3][3];
vector<vector<int>> masks[3][3][3][3];
// precompute itu incompatible pairsnya gmn aja
int main() {
ios_base::sync_with_stdio(0); cin.tie(NULL);
int n;
cin >> n;
// coba cek tiap possibility pengambilan
// max pengambilan cmn 3?
int e[n + 1][3];
for(int i = 0; i < 3; ++i) {
for(int j = 1; j <= n; ++j) {
char x;
cin >> x;
e[j][i] = to_num(x);
}
}
for(int i = 1; i <= n; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
for(int l = 0; l < 3; ++l) {
pref[i][j][k][l] += pref[i - 1][j][k][l];
}
}
}
pref[i][e[i][0]][e[i][1]][e[i][2]]++;
}
int q;
cin >> q;
set<pair<pair<int, int>, int>> segments;
for(int i = 1; i <= n; ++i) {
char x;
cin >> x;
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
for(int l = 0; l < 3; ++l) {
cnt[j][k][l][to_num(x)] += pref[i][j][k][l] - pref[i - 1][j][k][l];
}
}
}
segments.insert(make_pair(make_pair(i, i), to_num(x)));
}
string choice[3] = {"J", "O", "I"};
vector<vector<int>> triplets;
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
triplets.push_back({i, j, k});
}
}
}
// utk tiap triple consider tiap pengambilan dengan triple itu sendiri, apa bisa buat char tertentu?
for(auto p : triplets) {
for(int i = 0; i < 3; ++i) {
string tmp = choice[p[i]];
for(int j = 0; j < 3; ++j) {
tmp = operate(tmp, choice[p[j]]);
for(int k = 0; k < 3; ++k) {
tmp = operate(tmp, choice[p[k]]);
possible[p[0]][p[1]][p[2]][to_num(tmp)] = 1;
masks[p[0]][p[1]][p[2]][to_num(tmp)].push_back({i, j, k});
}
}
}
}
for(int trip = 0; trip < triplets.size(); ++trip) {
for(int trip2 = 0; trip2 < triplets.size(); ++trip2) {
vector<int> p1 = triplets[trip], p2 = triplets[trip2];
for(int i = 0; i < 3; ++i) {
string tmp1 = choice[p1[i]];
string tmp2 = choice[p2[i]];
for(int j = 0; j < 3; ++j) {
tmp1 = operate(tmp1, choice[p1[j]]);
tmp2 = operate(tmp2, choice[p2[j]]);
for(int k = 0; k < 3; ++k) {
tmp1 = operate(tmp1, choice[p1[k]]);
tmp2 = operate(tmp2, choice[p2[k]]);
compatible[p1[0]][p1[1]][p1[2]][to_num(tmp1)][p2[0]][p2[1]][p2[2]][to_num(tmp2)] = 1;
}
}
}
}
}
// coba permutasi size 1, 2, 3
// given same sequence tp resultnya beda -> pasti gabisa -> O(81Q) -> 1.6e7
// klo misal ga ada yg beda, berarti max ada 27 aja
// klo 27, nanti cek O(27^2*Q) -> 1.4e8
// total O(81Q)
bool ans = 1;
vector<vector<int>> a;
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
for(int l = 0; l < 3; ++l) {
if(cnt[i][j][k][l] && !possible[i][j][k][l])
ans = 0;
if(cnt[i][j][k][l])
a.push_back({i, j, k, l});
}
}
}
}
int res[3][3][3];
memset(res, 0, sizeof(res));
for(int i = 0; i < a.size(); ++i) {
for(auto j : masks[a[i][0]][a[i][1]][a[i][2]][a[i][3]]) {
++res[j[0]][j[1]][j[2]];
}
}
int mx = 0;
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k)
mx = max(mx, res[i][j][k]);
}
}
if(ans && mx == n)
cout << "Yes" << endl;
else
cout << "No" << endl;
while(q--) {
// jalankan kode update
int l, r; char x;
cin >> l >> r >> x;
while(segments.lower_bound(mp(make_pair(l, 0), 0)) != segments.end() && (*segments.lower_bound(mp(make_pair(l, 0), 0))).fi.se <= r) {
pair<pair<int, int>, int> tmp = *segments.lower_bound(mp(mp(l, 0), 0));
int cl = tmp.fi.se, cr = tmp.fi.fi, type = tmp.se;
segments.erase(tmp);
if(cl < l) {
segments.ins(mp(mp(l - 1, cl), type));
}
if(cr > r) {
segments.ins(mp(mp(cr, r + 1), type));
}
cl = max(l, cl);
cr = min(r, cr);
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
cnt[i][j][k][type] -= pref[cr][i][j][k] - pref[cl - 1][i][j][k];
cnt[i][j][k][to_num(x)] += pref[cr][i][j][k] - pref[cl - 1][i][j][k];
// cek mask yg bs buat i, j, k jadi type?
}
}
}
}
segments.ins(mp(mp(r, l), to_num(x)));
// kode cek answer
bool ans = 1;
vector<vector<int>> a;
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k) {
for(int l = 0; l < 3; ++l) {
if(cnt[i][j][k][l] && !possible[i][j][k][l])
ans = 0;
if(cnt[i][j][k][l])
a.push_back({i, j, k, l});
}
}
}
}
if(!ans) {
cout << "No" << endl;
continue;
}
// cari subset yg compatiblenya terbanyak?
int res[3][3][3];
memset(res, 0, sizeof(res));
for(int i = 0; i < a.size(); ++i) {
for(auto j : masks[a[i][0]][a[i][1]][a[i][2]][a[i][3]]) {
++res[j[0]][j[1]][j[2]];
}
}
int mx = 0;
for(int i = 0; i < 3; ++i) {
for(int j = 0; j < 3; ++j) {
for(int k = 0; k < 3; ++k)
mx = max(mx, res[i][j][k]);
}
}
if(ans && mx == n)
cout << "Yes" << endl;
else
cout << "No" << endl;
}
return 0;
}
컴파일 시 표준 에러 (stderr) 메시지
Main.cpp: In function 'std::string operate(std::string, std::string)':
Main.cpp:24:24: warning: comparison of integer expressions of different signedness: 'int' and 'std::__cxx11::basic_string<char>::size_type' {aka 'long unsigned int'} [-Wsign-compare]
24 | for(int it = 0; it < a.size(); ++it) {
| ~~~^~~~~~~~~~
Main.cpp:27:28: warning: variable 'i' set but not used [-Wunused-but-set-variable]
27 | bool j = 0, o = 0, i = 0;
| ^
Main.cpp: In function 'int main()':
Main.cpp:164:28: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::vector<int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
164 | for(int trip = 0; trip < triplets.size(); ++trip) {
| ~~~~~^~~~~~~~~~~~~~~~~
Main.cpp:165:34: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::vector<int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
165 | for(int trip2 = 0; trip2 < triplets.size(); ++trip2) {
| ~~~~~~^~~~~~~~~~~~~~~~~
Main.cpp:203:22: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::vector<int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
203 | for(int i = 0; i < a.size(); ++i) {
| ~~^~~~~~~~~~
Main.cpp:268:26: warning: comparison of integer expressions of different signedness: 'int' and 'std::vector<std::vector<int> >::size_type' {aka 'long unsigned int'} [-Wsign-compare]
268 | for(int i = 0; i < a.size(); ++i) {
| ~~^~~~~~~~~~
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