제출 #749510

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
749510		SanguineChameleon	앨리스, 밥, 서킷 (APIO23_abc)	C++17	12 / 100	160 ms	12488 KiB

abc

#include <bits/stdc++.h>
#include "abc.h"
using namespace std;

// you may find the definitions useful
const int OP_ZERO    = 0;  // f(OP_ZERO,    x0, x1) = 0
const int OP_NOR     = 1;  // f(OP_NOR,     x0, x1) = !(x0 || x1)
const int OP_GREATER = 2;  // f(OP_GREATER, x0, x1) = (x0 > x1)
const int OP_NOT_X1  = 3;  // f(OP_NOT_X1,  x0, x1) = !x1
const int OP_LESS    = 4;  // f(OP_LESS,    x0, x1) = (x0 < x1)
const int OP_NOT_X0  = 5;  // f(OP_NOT_X0,  x0, x1) = !x0
const int OP_XOR     = 6;  // f(OP_XOR,     x0, x1) = (x0 ^ x1)
const int OP_NAND    = 7;  // f(OP_NAND,    x0, x1) = !(x0 && x1)
const int OP_AND     = 8;  // f(OP_AND,     x0, x1) = (x0 && x1)
const int OP_EQUAL   = 9;  // f(OP_EQUAL,   x0, x1) = (x0 == x1)
const int OP_X0      = 10; // f(OP_X0,      x0, x1) = x0
const int OP_GEQ     = 11; // f(OP_GEQ,     x0, x1) = (x0 >= x1)
const int OP_X1      = 12; // f(OP_X1,      x0, x1) = x1
const int OP_LEQ     = 13; // f(OP_LEQ,     x0, x1) = (x0 <= x1)
const int OP_OR      = 14; // f(OP_OR,      x0, x1) = (x0 || x1)
const int OP_ONE     = 15; // f(OP_ONE,     x0, x1) = 1


// Alice
int // returns la
alice(
	/*  in */ const int n,
	/*  in */ const char names[][5],
	/*  in */ const unsigned short numbers[],
	/* out */ bool outputs_alice[]
) {
	for (int i = 0; i < 16; i++) {
		outputs_alice[i] = (numbers[0] >> i) & 1;
	}
	return 16;
}


// Bob
int // returns lb
bob(
	/*  in */ const int m,
	/*  in */ const char senders[][5],
	/*  in */ const char recipients[][5],
	/* out */ bool outputs_bob[]
) {
	for (int i = 0; i < m; i++) {
		outputs_bob[i] = 1;
	}
	for (int i = m; i < 1024; i++) {
		outputs_bob[i] = 0;
	}
	return 1024;
}

int *operations;
int (*operands)[2];
int cnt;
int ZERO_GATE;
int ONE_GATE;

int gate(int op, int x, int y) {
	operations[cnt] = op;
	operands[cnt][0] = x;
	operands[cnt][1] = y;
	return cnt++;
}

pair<int, int> add(int x, int y, int z) {
	int sum1 = gate(OP_XOR, x, y);
	int rem1 = gate(OP_AND, x, y);
	int sum2 = gate(OP_XOR, sum1, z);
	int rem2 = gate(OP_AND, sum1, z);
	return make_pair(sum2, gate(OP_OR, rem1, rem2));
}

vector<int> add(vector<int> num1, vector<int> num2) {
	vector<int> res(16);
	int rem = ZERO_GATE;
	for (int i = 0; i < 16; i++) {
		auto p = add(num1[i], num2[i], rem);
		res[i] = p.first;
		rem = p.second;
	}
	return res;
}

vector<int> mul(vector<int> num, int x) {
	vector<int> res(16);
	for (int i = 0; i < 16; i++) {
		res[i] = gate(OP_AND, num[i], x);
	}
	return res;
}

// Circuit
int // returns l
circuit(
	/*  in */ const int la,
	/*  in */ const int lb,
	/* out */ int _operations[],
	/* out */ int _operands[][2],
	/* out */ int outputs_circuit[][16]
) {
	operations = _operations;
	operands = _operands;
	cnt = la + lb;
	ZERO_GATE = gate(OP_ZERO, 0, 0);
	ONE_GATE = gate(OP_ONE, 0, 0);
	vector<int> num(16);
	for (int i = 0; i < 16; i++) {
		num[i] = i;
	}
	vector<int> res(16, ZERO_GATE);
	for (int i = 0; i < 1024; i++) {
		res = add(res, mul(num, 16 + i));
	}
	for (int i = 0; i < 16; i++) {
		outputs_circuit[0][i] = res[i];
	}
	return cnt;
}

• Subtask 1: 4 / 4
• Subtask 2: 4 / 4
• Subtask 3: 4 / 4
• Subtask 4: 0 / 24
• Subtask 5: 0 / 24
• Subtask 6: 0 / 6
• Subtask 7: 0 / 18
• Subtask 8: 0 / 10
• Subtask 9: 0 / 6