제출 #747453

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
747453		ibsha	Art Exhibition (JOI18_art)	C++17	0 / 100	0 ms	212 KiB

art

/*
                                  ⢀⡴⠑⡄⠀⠀⠀⠀⠀⠀⠀⣀⣀⣤⣤⣤⣀⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀
                                  ⠸⡇⠀⠿⡀⠀⠀⠀⣀⡴⢿⣿⣿⣿⣿⣿⣿⣿⣷⣦⡀⠀⠀⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠑⢄⣠⠾⠁⣀⣄⡈⠙⣿⣿⣿⣿⣿⣿⣿⣿⣆⠀⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⢀⡀⠁⠀⠀⠈⠙⠛⠂⠈⣿⣿⣿⣿⣿⠿⡿⢿⣆⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⢀⡾⣁⣀⠀⠴⠂⠙⣗⡀⠀⢻⣿⣿⠭⢤⣴⣦⣤⣹⠀⠀⠀⢀⢴⣶⣆
                                  ⠀⠀⢀⣾⣿⣿⣿⣷⣮⣽⣾⣿⣥⣴⣿⣿⡿⢂⠔⢚⡿⢿⣿⣦⣴⣾⠁⠸⣼⡿
                                  ⠀⢀⡞⠁⠙⠻⠿⠟⠉⠀⠛⢹⣿⣿⣿⣿⣿⣌⢤⣼⣿⣾⣿⡟⠉⠀⠀⠀⠀⠀
                                  ⠀⣾⣷⣶⠇⠀⠀⣤⣄⣀⡀⠈⠻⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀
                                  ⠀⠉⠈⠉⠀⠀⢦⡈⢻⣿⣿⣿⣶⣶⣶⣶⣤⣽⡹⣿⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⠀⠉⠲⣽⡻⢿⣿⣿⣿⣿⣿⣿⣷⣜⣿⣿⣿⡇⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⠀⠀⢸⣿⣿⣷⣶⣮⣭⣽⣿⣿⣿⣿⣿⣿⣿⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⣀⣀⣈⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠇⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⢿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⠃⠀⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⠀⠹⣿⣿⣿⣿⣿⣿⣿⣿⣿⣿⡿⠟⠁⠀⠀⠀⠀⠀⠀⠀⠀⠀
                                  ⠀⠀⠀⠀⠀⠀⠀⠀⠀⠉⠛⠻⠿⠿⠿⠿⠛⠉
*/
#include <bits/stdc++.h>
using namespace std;
#define fastio ios::sync_with_stdio(0);cin.tie(0);cout.tie(0);
#define MOD 1000000007
#define endl '\n'
#define pb(v,i) (v).push_back(i)
#define vll vector<ll>
#define pll pair<ll,ll>
typedef long long ll;



__int128 fastpow(ll base,ll exp){__int128 result=1;while (exp){if (exp%2==1) result*=base;exp/=2;base*=base;}return result;}
bool isprime(ll x){for (ll i=2;i*i<=x;i++){if (x%i==0) return 0;}return 1;}
// bool issorted(auto i, auto j){ i++; for (;i!=j;i++){if (*i<*(i-1)) return 0;}return 1;}
bool cmp(ll i, ll j){ return i>j;};
bool cmp2(pll i, pll j){ // for task specific sorts
  if (i.first==j.first) return i.second > j.second;
  return i.first<j.first;
}


signed main(){

  fastio
  ll n;
  cin >> n;
  pll a[n];
  ll ans=LLONG_MIN;
  ll sum=0;
  for (int i=0;i<n;i++){
    cin >> a[i].first >> a[i].second;
    sum+=a[i].second;
  }
  sort(a,a+n,cmp2);

  ll l=0,r=n-1;
  while (l<=r){
    ans=max(ans,sum-(a[r].first-a[l].first));
    if (l!=r){
      ll ml,mr;
      ml=(sum-a[l].second)-(a[r].first-a[l+1].first);
      mr=(sum-a[r].second)-(a[r-1].first-a[l].first);
      if (ml>mr){
        sum-=a[l].second;
        l++;
      } else{ sum-=a[r].second; r--;}
    }
    else break;
  }

  cout << ans;
}

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• Subtask 2: 0 / 20
• Subtask 3: 0 / 20
• Subtask 4: 0 / 50