This submission is migrated from previous version of oj.uz, which used different machine for grading. This submission may have different result if resubmitted.
#include "bits/stdc++.h"
using namespace std;
const int MAXN = 1e5+5;
vector< vector<int> > adj(MAXN);
bool visited[MAXN];
long long sz[MAXN];
long long bgsz[MAXN];
int par[MAXN];
long long add[MAXN];
int n, m;
int find(int v)
{
if(par[v] == v)
return v;
return par[v] = find(par[v]);
}
void merge(int a, int b)
{
a = find(a), b = find(b);
if(a == b)
return;
if(bgsz[a] < bgsz[b])
swap(a, b);
par[b] = a;
bgsz[a] += bgsz[b];
}
pair<long long, bool> subtask3(int v, int p)
{
pair<long long, bool> ans = {1, false};
visited[v] = true;
for(int e : adj[v])
{
if(e == p)
continue;
if(visited[e]) {
ans.second = true;
continue;
}
pair<long long, bool> temp = subtask3(e, v);
ans.first += temp.first;
ans.second |= temp.second;
}
return ans;
}
long long subtask5(int v, int p)
{
long long ans = 0;
visited[v] = true;
sz[v] = 1;
long long chi_size = 0;
for(int e : adj[v])
{
if(e == p)
continue;
ans += subtask5(e, v);
sz[v] += sz[e];
chi_size += sz[e];
}
int bigpar = find(v);
long long par_size = bgsz[bigpar] - chi_size - 1;
ans += par_size * chi_size;
//cout << bgsz[bigpar] << "\n";
for(int e : adj[v])
{
if(e == p)
continue;
ans += sz[e] * (bgsz[bigpar] - sz[e] - 1LL);
}
return ans;
}
int main()
{
long long temp = 0;
add[0] = 0;
for(long long i = 1; i < MAXN; i++)
{
temp += i;
add[i] = add[i - 1] + temp;
par[i] = i;
bgsz[i] = 1;
}
cin >> n >> m;
for(int i = 1; i <= m; i++)
{
int f, s;
cin >> f >> s;
adj[f].push_back(s);
adj[s].push_back(f);
merge(f, s);
}
int max_size = 0;
for(int i = 1; i <= n; i++)
{
max_size = max(max_size, (int)adj[i].size());
}
long long ans = 0;
if(max_size <= 2) // Subtask 3
{
for(int i = 1; i <= n; i++)
{
if(visited[i])
continue;
pair<long long, bool> curr = subtask3(i, -1);
if(curr.second)
{
ans += curr.first * (curr.first - 1) * (curr.first - 2);
} else if(curr.first >= 3)
{
ans += add[curr.first - 2] * 2LL;
}
}
} else //Subtask 4, 5
{
for(int i = 1; i <= n; i++)
{
if(visited[i])
continue;
ans += subtask5(i, -1);
}
}
cout << ans << "\n";
}
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