제출 #739616

#제출 시각아이디문제언어결과실행 시간메모리
739616Nirjhor경주 (Race) (IOI11_race)C++17
100 / 100
853 ms59556 KiB
#include "race.h" #include <bits/stdc++.h> #include <ext/pb_ds/assoc_container.hpp> using namespace std; using namespace __gnu_pbds; const int N = 200010; bool bad[N]; long long weight[N]; vector <pair <int, int>> g[N]; int sub[N], ans, ptr, h[N], in[N], out[N], flat[N], target; // compute subtree sizes void trav (int u, int p = -1) { sub[u] = 1; for (auto [v, w] : g[u]) if (v != p and !bad[v]) { trav(v, u); sub[u] += sub[v]; } } // find centroid int centroid (int u, int bound, int p = -1) { for (auto [v, w] : g[u]) if (v != p and !bad[v] and sub[v] > bound) { return centroid(v, bound, u); } return u; } // flatten the tree, compute information from root (centroid) to other nodes void go (int u, int p = -1, int depth = 0, long long sum = 0) { flat[++ptr] = u, in[u] = ptr; h[u] = depth, weight[u] = sum; for (auto [v, w] : g[u]) if (v != p and !bad[v]) { go(v, u, depth + 1, sum + w); } out[u] = ptr; } // centroid decomposition routine void decompose (int u = 0) { trav(u); int root = centroid(u, sub[u] / 2); ptr = 0; go(root); // data structure for merging two pieces gp_hash_table <long long, int> smallest; smallest[0] = 0; for (auto [u, w] : g[root]) if (!bad[u]) { // query for (int i = in[u]; i <= out[u]; ++i) { int v = flat[i]; long long required = target - weight[v]; if (smallest.find(required) != smallest.end()) { ans = min(ans, h[v] + smallest[required]); } } // update for (int i = in[u]; i <= out[u]; ++i) { int v = flat[i]; if (smallest.find(weight[v]) == smallest.end()) { smallest[weight[v]] = h[v]; } else { smallest[weight[v]] = min(smallest[weight[v]], h[v]); } } } // remove centroid and proceed recursively bad[root] = true; for (auto [v, w] : g[root]) if (!bad[v]) decompose(v); } int best_path (int N, int K, int H[][2], int L[]) { for (int i = 0; i < N - 1; ++i) { int u = H[i][0], v = H[i][1], w = L[i]; g[u].emplace_back(v, w), g[v].emplace_back(u, w); } ans = INT_MAX, target = K; decompose(); if (ans == INT_MAX) ans = -1; return ans; }
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