이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include "koala.h"
#include <bits/stdc++.h>
using namespace std;
int minValue(int N, int W) {
// TODO: Implement Subtask 1 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
int A[N], B[N];
for (int i = 0; i < N; i++) A[i] = i == 0;
playRound(A, B);
for (int i = 0; i < N; i++) {
if (B[i] <= A[i]) return i;
}
return -1;
}
int maxValue(int N, int W) {
// TODO: Implement Subtask 2 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
vector<int> candidates(N);
iota(candidates.begin(), candidates.end(), 0);
while (candidates.size() != 1) {
int cnt = W / candidates.size();
int A[N], B[N];
for (int i = 0; i < N; i++) A[i] = 0;
for (int i : candidates) A[i] = cnt;
playRound(A, B);
vector<int> nc;
for (int i : candidates) {
if (B[i] > A[i]) nc.emplace_back(i);
}
candidates = nc;
}
return candidates[0];
}
int greaterValue(int N, int W) {
// TODO: Implement Subtask 3 solution here.
// You may leave this function unmodified if you are not attempting this
// subtask.
return 0;
}
void allValues(int N, int W, int *P) {
if (W == 2 * N) {
// TODO: Implement Subtask 4 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
} else {
// TODO: Implement Subtask 5 solution here.
// You may leave this block unmodified if you are not attempting this
// subtask.
}
}
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