이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
#define fi first
#define se second
#define mp make_pair
#define pb push_back
#define fbo find_by_order
#define ook order_of_key
#define INF 1e18
#define ret return
typedef long long ll;
typedef pair<int,int> ii;
typedef vector<int> vi;
typedef vector < pair<int, int> > vii;
typedef long double ld;
typedef tree<pair<int,int>, null_type, less<pair<int,int> >, rb_tree_tag, tree_order_statistics_node_update> pbds;
typedef set<int>::iterator sit;
typedef map<int,int>::iterator mit;
typedef vector<int>::iterator vit;
const ll MOD = 1e9+7;
struct mat{
	ll a[2][2];
	void ini(ll a1, ll a2, ll a3, ll a4){
		a[0][0]=a1;
		a[0][1]=a2;
		a[1][0]=a3;
		a[1][1]=a4;
	}
};
ll add(ll a, ll b){
	ll res=(a+MOD)+(b+MOD);
	res%=MOD;
	ret res;
}
ll mult(ll a, ll b){
	ll res = (a+MOD)*b+(MOD);
	res%=MOD;
	ret res;
}
mat mat_mult(mat A, mat B){
	mat res;
	for(int i = 0; i < 2; i++){
		for(int j = 0; j < 2; j++){
			res.a[0][0]=add(mult(A.a[0][0],B.a[0][0]),mult(A.a[0][1],B.a[1][0]));
			res.a[0][1]=add(mult(A.a[0][0],B.a[0][1]),mult(A.a[0][1],B.a[1][1]));
			res.a[1][0]=add(mult(A.a[1][0],B.a[0][0]),mult(A.a[1][1],B.a[1][0]));
			res.a[1][1]=add(mult(A.a[1][0],B.a[0][1]),mult(A.a[1][1],B.a[1][1]));
		}
	}
	ret res;
}
ll a[111];
mat mat_exp(mat a, int n){
	if(n==1)ret a;
	if(n%2){
		mat res = mat_exp(a,n-1);
		ret mat_mult(res,a);
	}
	else{
		mat res = mat_exp(a,n/2);
		ret mat_mult(res,res);
	}
}
mat cur, r;
ll solve(ll p, int q){
	if(p==0){
		ret 1;
	}
	if(q==0){
		ret 0;
	}
	ll res = 0;
	for(int i = q; i >= 1; i--){
		if(mat_exp(r,i).a[0][0]<=p){
			res=add(res,solve(p-mat_exp(r,i).a[0][0],i-1));
		}
	}
	ret res;
}
int main(){
	int n;
	cin >> n;
	ll p=0;
	cur.ini(1,1,1,0);
	r=cur;
	int q = 1;
	for(int i = 0; i < n; i++){
		cin >> a[i];
		p+=mat_exp(r,a[i]).a[0][0];
		while(mat_mult(cur,r).a[0][0]<=p){
			cur=mat_mult(cur,r);
			q++;
		}
		cout << solve(p,q) << endl;
	}
}
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