Submission #73027

#TimeUsernameProblemLanguageResultExecution timeMemory
73027BenqRanklist Sorting (BOI07_sorting)C++14
30 / 100
1070 ms648 KiB
#pragma GCC optimize ("O3") #pragma GCC target ("sse4") #include <bits/stdc++.h> #include <ext/pb_ds/tree_policy.hpp> #include <ext/pb_ds/assoc_container.hpp> #include <ext/rope> using namespace std; using namespace __gnu_pbds; using namespace __gnu_cxx; typedef long long ll; typedef long double ld; typedef complex<ld> cd; typedef pair<int, int> pi; typedef pair<ll,ll> pl; typedef pair<ld,ld> pd; typedef vector<int> vi; typedef vector<ld> vd; typedef vector<ll> vl; typedef vector<pi> vpi; typedef vector<pl> vpl; typedef vector<cd> vcd; template <class T> using Tree = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; #define FOR(i, a, b) for (int i=a; i<(b); i++) #define F0R(i, a) for (int i=0; i<(a); i++) #define FORd(i,a,b) for (int i = (b)-1; i >= a; i--) #define F0Rd(i,a) for (int i = (a)-1; i >= 0; i--) #define sz(x) (int)(x).size() #define mp make_pair #define pb push_back #define f first #define s second #define lb lower_bound #define ub upper_bound #define all(x) x.begin(), x.end() const int MOD = 1000000007; const ll INF = 1e18; const int MX = 100001; int n; vi s; void compress() { ios_base::sync_with_stdio(0); cin.tie(0); cin >> n; s.resize(n); map<int,int> m; F0R(i,n) { cin >> s[i]; m[s[i]] = 0; } int co = 0; for (auto& a: m) a.s = co++; for (int& i: s) i = n-1-m[i]; } pair<int,vpi> test(int z) { vpi S; F0R(i,sz(s)) S.pb({s[i],1}); int lst = -1; F0R(i,n) { if (z&(1<<i)) S[i].s = 0; else { if (S[i].f < lst) return {MOD,{}}; lst = S[i].f; } } vpi v; int cur = 0; F0Rd(i,n) { int ind = 0; while (S[ind].f != i) ind ++; if (S[ind].s) continue; cur += ind+1; S.erase(S.begin()+ind); int lst = 0; F0R(j,n-1) if (S[j].s && S[j].f < i) lst = j+1; cur += lst+1; S.insert(S.begin()+lst,{i,1}); v.pb({ind+1,lst+1}); } /*for (auto a: S) cout << a.f << " " << a.s << " | "; cout << "\n";*/ return {cur,v}; } int main() { compress(); pair<int,vpi> ans = {MOD,{}}; F0R(i,1<<n) ans = min(ans,test(i)); cout << sz(ans.s) << "\n"; for (auto a: ans.s) cout << a.f << " " << a.s << "\n"; } /* Look for: * the exact constraints (multiple sets are too slow for n=10^6 :( ) * special cases (n=1?) * overflow (ll vs int?) * array bounds * if you have no idea just guess the appropriate well-known algo instead of doing nothing :/ */
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