제출 #729492

#	제출 시각	아이디	문제	언어	결과	실행 시간	메모리
729492		Blistering_Barnacles	게임 (IOI13_game)	C++11	0 / 100	1 ms	1108 KiB

game

#include "game.h"
//Billions of bilious blue blistering barnacles in a thundering typhoon!
#pragma GCC optimize("Ofast,fast-math,unroll-loops")
#pragma GCC target("avx2,fma")
#include<bits/stdc++.h>
#define fast ios::sync_with_stdio(0) , cin.tie(0)
#define F first
#define S second
#define pb push_back
#define vll vector< ll >
#define vi vector< int >
#define pll pair< ll , ll >
#define pi pair< int , int >
#define all(s) s.begin() , s.end()
#define sz(s) s.size()
#define str string
#define mdx ((sx + ex) / 2)
#define mdy ((sy + ey) / 2)
#define mid ((l + r) / 2)
#define msdp(dp) memset(dp , -1 , sizeof dp)
#define mscl(dp) memset(dp , 0 , sizeof dp)
#define C continue
#define R return
#define B break
#define lxx nodex * 2
#define rxx nodex * 2 + 1
#define lxy nodey * 2
#define rxy nodey * 2 + 1
#define br(dosomething) {dosomething; break;}
#define co(dosomething) {dosomething ; continue;}
using namespace std;
typedef long long ll;
long long gcd2(long long X, long long Y) {
    long long tmp;
    while (X != Y && Y != 0) {
        tmp = X;
        X = Y;
        Y = tmp % Y;
    }
    return X;
}
ll n , m , k ;
void init(int r, int c) {
    n = r , m = c ;
}
ll tree[8005][8005] ;
void updatey(ll sy , ll ey , ll nodey , ll sx , ll ex , ll nodex , ll x , ll y , ll val){
    if(sy == ey){
        if(sx == ex)tree[nodex][nodey] = val ;
        else tree[nodex][nodey] = gcd2(tree[lxx][nodey] , tree[rxx][nodey]) ;
        R ;
    }
    if(y <= mdy)updatey(sy , mdy , lxy , sx , ex , nodex , x , y , val) ;
    else updatey(mdy + 1 , ey , rxy , sx , ex , nodex , x , y , val) ;
    tree[nodex][nodey] = gcd2(tree[nodex][lxy] , tree[nodex][rxy]) ;
}
void updatex(ll sx , ll ex , ll nodex , ll x , ll y , ll val){
    if(sx != ex){
        if(x <= mdx)updatex(sx , mdx , lxx , x , y  , val) ;
        else updatex(mdx + 1 , ex , rxx , x , y , val) ;
    }
    updatey(0 , m - 1 , 1 , sx , ex , nodex , x , y , val) ;
}
ll queryy(ll sy , ll ey , ll nodey , ll nodex , ll ly , ll ry){
    if(sy > ry || ey < ly)R 0 ;
    if(ly <= sy && ey <= ry)R tree[nodex][nodey] ;
    R gcd2(queryy(sy , mdy , lxy , nodex , ly , ry) , queryy(mdy + 1 , ey , nodey , nodex , ly , ry)) ;
}
ll queryx(ll sx , ll ex , ll nodex , ll lx , ll ly , ll rx , ll ry){
    if(sx > rx || ex < lx)R 0 ;
    if(lx <= sx && ex <= rx){
        R queryy(0 , m - 1 , 1 , nodex , ly , ry) ;
    }
    R gcd2(queryx(sx , mdx , lxx , lx , ly , rx , ry) , queryx(mdx + 1 , ex , rxx , lx , ly , rx , ry)) ;
}
void update(int P, int Q, long long K) {
    updatex(0 , n - 1 , 1 , P , Q , K) ;
}

long long calculate(int P, int Q, int U, int V) {
    R queryx(0 , n - 1 , 1 , P , Q , U , V) ;
}

• Subtask 1: 0 / 10
• Subtask 2: 0 / 27
• Subtask 3: 0 / 26
• Subtask 4: 0 / 17
• Subtask 5: 0 / 20