제출 #729079

#제출 시각아이디문제언어결과실행 시간메모리
729079Vanilla수열 (APIO14_sequence)C++17
39 / 100
2025 ms131072 KiB
#include <bits/stdc++.h> #include <fstream> #include <ext/pb_ds/assoc_container.hpp> #include <ext/pb_ds/tree_policy.hpp> using namespace __gnu_pbds; using namespace std; template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>; struct custom_hash {static uint64_t splitmix64(uint64_t x) {x += 0x9e3779b97f4a7c15;x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;x = (x ^ (x >> 27)) * 0x94d049bb133111eb;return x ^ (x >> 31);}size_t operator()(uint64_t x) const {static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();return splitmix64(x + FIXED_RANDOM);}}; // string __fname = ""; ifstream in (__fname + ".in"); ofstream out (__fname + ".out"); // #define cin in // #define cout out #define int64 long long #define uint64 unsigned long long #define x first #define y second #define pb push_back #define pii pair <int, int> #define pii64 pair <int64, int64> #define db(x) cout << "> " << #x << ": " << (x) << "\n" #define qr queries() #define yn(x) if (x) {ctn("Yes");}else {ctn("No");} void solve(int); void queries(){int n;cin >> n;for (int i = 1; i <= n; i++) solve(i);} template<class T>T ceildiv(T a, T b) {return a / b + !!(a % b);} template<class T>T gcd (T a, T b){return (b ? gcd(b, a % b): a);} template<class T>T lcm (T a, T b){return a * b / gcd(a, b);} // // // // // // // // // // // // // // // // // // // // // // /* TEMPLATE - VANILLA */ // // // // // // // // // // // // // // // // // // // // // // const int ddx[] = {-1, -1, 0, 1, 1, 1, 0, -1}; const int ddy[] = {0, 1, 1, 1, 0, -1, -1, -1}; const int dx[] = {-1, 0, 1, 0}; const int dy[] = {0, 1, 0, -1}; const double pi = 3.14159265359; const double eps = 1e-6; const int64 hash_inv = 940594066; const int64 hash_p = 101; const int64 mod = 1e9 + 7; const int maxn = 1e5 + 2; const int maxk = 201; int64 dp[maxn][maxk]; // dp[i][j] -> scor maxim folosind primele i elemente repartizate folosind j splits si ultimul split fiind la elementul i int64 pref [maxn]; int64 dad[maxn][maxk]; void solve(int id){ return; } int64 calc (int64 i1, int64 i2, int64 i3) { // [i1;i3] -> [i1; i2 - 1] + [i2; i3] return (pref[i3] - pref[i2 - 1]) * (pref[i2 - 1] - pref[i1 - 1]); } int main(){ ios_base::sync_with_stdio(0); cin.tie(0); cout << fixed; cout << setprecision(10); int n,k; cin >> n >> k; for (int i = 1; i <= n; i++){ int x; cin >> x; pref[i] = pref[i-1] + x; } if (n == 1) { cout << "0\n"; return 0; } for (int i = 0; i <= n; i++) for (int j = 1; j <= k; j++) dp[i][j] = -1e15; for (int t = 1; t <= k; t++){ for (int i = 1; i < n; i++){ for (int j = 1; j <= i; j++){ // [j; n] -> [j; i] + [i + 1; n] int64 nc = dp[j-1][t-1] + calc(j, i + 1, n); if (nc > dp[i][t]) { dp[i][t] = nc; dad[i][t] = j-1; } } } } int64 mx = 0, mxi = 0; for (int i = 1; i <= n; i++){ if (dp[i][k] > mx) { mx = dp[i][k]; mxi = i; } } vector <int> v; v.push_back(mxi); while ((mxi = dad[mxi][k--]) > 0) { v.push_back(mxi); } cout << mx << "\n"; reverse(v.begin(), v.end()); for (int i: v) { cout << i << " "; } return 0; }
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