이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
// yolo
#pragma GCC optimize("Ofast,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <bits/stdc++.h>
using namespace std;
string rk = "x-"; vector<string> spstr,rgstr;
string c1 = "xxx";
vector<string> c2,c3,c4,c5,c6,c7;
int n,a[11]; int64_t dp[11][22][22][301]; // first i frames, carry amount from previous i, carry amount from i, score after i
// carry is -1 if we don't add
string s;
void solve(){
memset(dp,0,sizeof dp);
cin >> n >> s; s = ' ' + s;
for(int i = 1; i <= n; i++) cin >> a[i];
auto can = [&](int i, string& t){
assert(t.size() == 2);
for(int j = 0; j < 2; j++){
char c = s[i+j]; if(c == '?') continue;
if(c != t[j]) return false;
}
return true;
};
auto can1 = [&](int i, string& t){
assert(t.size() == 3);
for(int j = 0; j < 3; j++){
char c = s[i+j];
if(c == '?') continue;
if(c != t[j]) return false;
}
return true;
};
dp[0][0][0][0] = 1;
auto add = [&](int64_t& x, int64_t y){
x = (x+y);
};
// solve normal
for(int i = 1; i <= n-1; i++){
// generate good strings
bool grk = can(2*i-1,rk);
vector<string> gsp,grg;
for(auto& t : spstr) if(can(2*i-1,t)) gsp.push_back(t);
for(auto& t : rgstr) if(can(2*i-1,t)) grg.push_back(t);
swap(gsp,spstr);
swap(grg,rgstr);
for(int j = -1; j <= 10; j++) for(int k = -1; k <= 20; k++){ // previous previous, previous carries
// strike
// our shot needs to make j zero, k non negative
int lo = 0, hi = 270;
if(a[i] != -1) lo = hi = a[i];
if(grk && (j == -1 || j-10 == 0) && (k == -1 || (k-10 >= 0 && k-10 <= 10))){
int nk = (k == -1 ? -1 : k-10);
// we can gain some more from carries if needed
for(int gain = 0; gain <= 20; gain++){
// l >= gain+10
//if(l-gain-10 < 0) break;
for(int l = max(lo,gain+10); l <= hi; l++) add(dp[i][nk+1][gain+1][l],dp[i-1][j+1][k+1][l-gain-10]);
}
}
// spare
if(k == -1 || k-10 == 0){
// TODO: opt break
for(auto& t : spstr){
// previous previous gets subtracted by fs, previous gets subtracted by 10
// both are gone after this frame, so need to become 0
int fs = t[0]-'0';
if(j != -1 && j-fs != 0) continue;
for(int gain = 0; gain <= 10; gain++){
//if(l-gain-10 < 0) break;
// add to previous slot to satisfy one bonus feature
for(int l = max(lo,gain+10); l <= hi; l++) add(dp[i][gain+1][0][l],dp[i-1][j+1][k+1][l-gain-10]);
}
}
}
// regular
for(auto& t : rgstr){
// previous previous gets subtracted by fs, previous gets subtracted by sn+fs
// both are gone after this frame, so need to become 0
int fs = t[0]-'0',sn = t[1]-'0';
if(j != -1 && j-fs != 0) continue;
if(k != -1 && k-fs-sn != 0) continue;
//if(l-fs-sn < 0) continue;
for(int l = max(lo,fs+sn); l <= hi; l++) add(dp[i][0][0][l],dp[i-1][j+1][k+1][l-fs-sn]);
}
/*
bool good = 0;
for(int z = 0; z <= 20 && !good; z++) for(int w = 0; w <= 20; w++) if(dp[i][z][w][l]){
good = 1;
break;
}
if(good) cout << l << " " << i << "\n"; */
}
swap(gsp,spstr);
swap(grg,rgstr);
}
// solve last
// preprocess equalities
vector<string> gc2,gc3,gc4,gc5,gc6,gc7;
for(auto& t : c2) if(can1(2*n-1,t)) gc2.push_back(t);
for(auto& t : c3) if(can1(2*n-1,t)) gc3.push_back(t);
for(auto& t : c4) if(can1(2*n-1,t)) gc4.push_back(t);
for(auto& t : c5) if(can1(2*n-1,t)) gc5.push_back(t);
for(auto& t : c6) if(can1(2*n-1,t)) gc6.push_back(t);
for(auto& t : c7) if(can1(2*n-1,t)) gc7.push_back(t);
bool gc1 = can1(2*n-1,c1);
swap(gc2,c2);
swap(gc3,c3);
swap(gc4,c4);
swap(gc5,c5);
swap(gc6,c6);
swap(gc7,c7);
int64_t ans = 0;
for(int j = -1; j <= 10; j++) for(int k = -1; k <= 20; k++){ // previous previous, previous carries
int lo = 0, hi = 300;
if(a[n] != -1) lo = hi = a[n];
for(int l = lo; l <= hi; l++){
int64_t res = 0;
// xxx
if(gc1 && (j == -1 || j-10 == 0) && (k == -1 || k-20 == 0) && l-30 >= 0){
add(res,dp[n-1][j+1][k+1][l-30]);
}
// xxA
// condition is same since bonus is only contributed in the first two shots
for(auto& t : c2) if((j == -1 || j-10 == 0) && (k == -1 || k-20 == 0)){
int ls = t[2]-'0';
if(l-20-ls < 0) continue;
add(res,dp[n-1][j+1][k+1][l-20-ls]);
}
// xA/
for(auto& t : c3) if(j == -1 || j-10 == 0){
int fs = t[1]-'0',sn = 10-fs;
if(k != -1 && k-10-fs != 0) continue;
if(l-20 < 0) continue;
add(res,dp[n-1][j+1][k+1][l-20]);
}
// xAB
for(auto& t : c4){
int fs = t[1]-'0',sn = t[2]-'0';
if(j != -1 && j-10 != 0) continue;
if(k != -1 && k-10-fs != 0) continue;
if(l-10-fs-sn < 0) continue;
add(res,dp[n-1][j+1][k+1][l-10-fs-sn]);
}
// A/x
for(auto& t : c5) if(k == -1 || k-10 == 0){
int fs = t[0]-'0';
if(j != -1 && j-fs != 0) continue;
if(l-20 < 0) continue;
add(res,dp[n-1][j+1][k+1][l-20]);
}
// A/B
for(auto& t : c6) if(k == -1 || k-10 == 0){
int fs = t[0]-'0',ls = t[2]-'0';
if(j != -1 && j-fs != 0) continue;
if(l-10-ls < 0) continue;
add(res,dp[n-1][j+1][k+1][l-10-ls]);
}
// AB-
for(auto& t : c7){
int fs = t[0]-'0',sn = t[1]-'0';
if(j != -1 && j-fs != 0) continue;
if(k != -1 && k-fs-sn != 0) continue;
if(l-fs-sn < 0) continue;
add(res,dp[n-1][j+1][k+1][l-fs-sn]);
}
ans += res;
}
}
swap(gc2,c2);
swap(gc3,c3);
swap(gc4,c4);
swap(gc5,c5);
swap(gc6,c6);
swap(gc7,c7);
cout << ans << "\n";
}
int main(){
cin.tie(0)->sync_with_stdio(0);
for(int i = 0; i <= 9; i++){
spstr.push_back(to_string(i) + "/");
c2.push_back("xx"+to_string(i));
c3.push_back("x"+to_string(i)+"/");
for(int j = 0; i+j < 10; j++){
rgstr.push_back(to_string(i)+to_string(j));
c4.push_back("x"+to_string(i)+to_string(j));
c7.push_back(to_string(i)+to_string(j)+"-");
}
c5.push_back(to_string(i)+"/x");
for(int j = 0; j <= 9; j++){
c6.push_back(to_string(i)+"/"+to_string(j));
}
}
int t; cin >> t; while(t--) solve();
}
// number of strs for frame: 10 + 1 + 10
// 5726805883325784576
컴파일 시 표준 에러 (stderr) 메시지
bow.cpp: In function 'void solve()':
bow.cpp:132:35: warning: unused variable 'sn' [-Wunused-variable]
132 | int fs = t[1]-'0',sn = 10-fs;
| ^~
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