이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <stdio.h>
#include <vector>
#include <queue>
#include <algorithm>
#include <iostream>
#include <string>
#include <bitset>
#include <map>
#include <set>
#include <tuple>
#include <string.h>
#include <math.h>
#include <random>
#include <functional>
#include <assert.h>
#include <math.h>
#include "prize.h"
#define all(x) (x).begin(), (x).end()
#define xx first
#define yy second
using namespace std;
template<typename T, typename Pr = less<T>>
using pq = priority_queue<T, vector<T>, Pr>;
using i64 = long long int;
using ii = pair<int, int>;
using ii64 = pair<i64, i64>;
vector<ii> finded;
int bigSize;
random_device rd;
mt19937 mt(rd());
int outL, outR;
int cntl(int x)
{
return upper_bound(all(finded), ii{ x, 1 << 30 }) - finded.begin() + outL;
}
int cntr(int x)
{
return finded.end() - lower_bound(all(finded), ii{ x, -1 }) + outR;
}
bool test(int l, int r)
{
if (l > r)
return false;
int m = (l + r) / 2;
int ml = m;
int mlL = 0, mlR = 0;
while (ml >= l)
{
if (any_of(all(finded), [ml](ii x) { return x.xx == ml; }))
{
ml--;
continue;
}
auto res = ask(ml);
if (res[0] + res[1] != bigSize)
{
finded.insert(lower_bound(all(finded), ii{ ml, res[0] + res[1] }), ii{ ml, res[0] + res[1] });
if (res[0] + res[1] == 0)
return true;
ml--;
}
else
{
mlL = res[0];
mlR = res[1];
break;
}
}
if (ml > l && mlL != cntl(ml - 1))
if (test(l, ml - 1))
return true;
if (m + 1 <= r && mlR - (m - ml) != cntr(m + 1))
if (test(m + 1, r))
return true;
return false;
}
int find_best(int n)
{
vector<int> indexs(n);
for (int i = 0; i < n; i++)
indexs[i] = i;
shuffle(all(indexs), mt);
vector<ii> ix;
for (int i = 0; i < min(n, 30); i++)
{
auto q = ask(indexs[i]);
ix.emplace_back(q[0] + q[1], indexs[i]);
}
sort(all(ix));
bigSize = ix.back().xx;
int bucket = 500;
vector<int> bs;
for (int i = 0; i < n; i += bucket)
bs.push_back(i);
shuffle(all(bs), mt);
for (auto& bi : bs)
{
finded.clear();
int l = bi, r = min(n - 1, bi + bucket - 1);
while (l < r)
{
auto q = ask(l);
if (q[0] + q[1] == 0)
return l;
if (q[0] + q[1] == bigSize)
{
outL = q[0];
break;
}
l++;
}
while (l < r)
{
auto q = ask(r);
if (q[0] + q[1] == 0)
return r;
if (q[0] + q[1] == bigSize)
{
outR = q[1];
break;
}
r--;
}
// 한 개도 없는 구간 pass
if (outL + outR == bigSize)
continue;
if (test(l + 1, r - 1))
{
for (auto& [k, v] : finded)
{
if (v == 0)
return k;
}
}
}
return 0;
}
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