oj.uz

답안 #725312

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
725312 2023-04-17T08:30:06 Z sunwukong123 Jail (JOI22_jail) C++14
0 / 100
 4 ms 8788 KB 
#include <bits/stdc++.h>
using namespace std;
#define int long long 
#define FOR(i,s,e) for(int i = s; i <= (int)e; ++i)
#define DEC(i,s,e) for(int i = s; i >= (int)e; --i)
#define IAMSPEED ios_base::sync_with_stdio(false); cin.tie(0);
#ifdef LOCAL
#define db(x) cerr << #x << "=" << x << "\n"
#define db2(x, y) cerr << #x << "=" << x << " , " << #y << "=" << y << "\n"
#define db3(a,b,c) cerr<<#a<<"="<<a<<","<<#b<<"="<<b<<","<<#c<<"="<<c<<"\n"
#define dbv(v) cerr << #v << ":"; for (auto ite : v) cerr << ite << ' '; cerr <<"\n"
#define dbvp(v) cerr << #v << ":"; for (auto ite : v) cerr << "{"  << ite.f << ',' << ite.s << "} "; cerr << "\n"
#define dba(a,ss,ee) cerr << #a << ":"; FOR(ite,ss,ee) cerr << a[ite] << ' '; cerr << "\n"
#define reach cerr << "LINE: " << __LINE__ << "\n";
#else
#define reach 
#define db(x)
#define db2(x,y)
#define db3(a,b,c)
#define dbv(v)
#define dbvp(v)
#define dba(a,ss,ee)
#endif
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
#define pb push_back
#define eb emplace_back
#define all(x) (x).begin(), (x).end()
#define f first 
#define s second
#define g0(x) get<0>(x)
#define g1(x) get<1>(x)
#define g2(x) get<2>(x)
#define g3(x) get<3>(x)
typedef pair <int, int> pi;
typedef tuple<int,int,int> ti3;
typedef tuple<int,int,int,int> ti4;
int rand(int a, int b) { return a + rng() % (b-a+1); }
const int MOD = 1e9 + 7;
const int inf = (int)1e9 + 500;
const long long oo = (long long)1e18 + 500;
template <typename T> void chmax(T& a, const T b) { a=max(a,b); }
template <typename T> void chmin(T& a, const T b) { a=min(a,b); }
const int MAXN = 120005;
int q; 
vector<int> adj[MAXN];
int S[MAXN], T[MAXN];
int dep[MAXN];
int twok[MAXN][20];
int pre[MAXN], post[MAXN];
int cnt;
int lift(int x, int k) {
	FOR(i,0,19){
		if((1<<i)&k)x=twok[x][i];
		if(x==-1)return -1;
	}
	return x;
}
int lca(int x, int y) {
	if(dep[x]>dep[y]) {
		int dd=dep[x]-dep[y];
		x=lift(x,dd);
	} else {
		int dd=dep[y]-dep[x];
		y=lift(y,dd);
	}
	if(x==y)return x;
	DEC(i,19,0){
		if(twok[x][i]!=twok[y][i]){
			x=twok[x][i];
			y=twok[y][i];
		}
	}
	return twok[x][0];
}
void dfs(int x, int p, int lvl) {
	pre[x]=cnt++;
	dep[x]=lvl;
	twok[x][0]=p;
	FOR(i,1,19){
		if(twok[x][i-1] == -1)continue;
		twok[x][i]=twok[twok[x][i-1]][i-1];
	}
	for(auto v:adj[x])if(v!=p) {
		dfs(v,x,lvl+1);
	}
	post[x]=cnt-1;
}
set<int> V[MAXN];
bool isanc(int par, int child) {
	if(pre[par]<pre[child] && post[par]>=post[child]) return 1;
	else return 0;
}
bool ispar(int par, int child) {
	if(pre[par]<=pre[child] && post[par]>=post[child]) return 1;
	else return 0;
}
bool onpath(int x, int y, int node) {
	db3(x,y,node);
	// check if node is on path from x to y
	if(ispar(y,x)) {
		return (ispar(y,node) && !isanc(x,node));
	}
	if(ispar(x,y)) {
		return (ispar(x,node) && !isanc(y,node));
	}
	int par=lca(x,y); 
	if(isanc(x,node)||isanc(y,node))return 0;
	if(ispar(par,node) && (ispar(node, x) || ispar(node, y))) return 1;
	else return 0;
}
int vis[MAXN];
bool dfs(int x) {
	bool res=0;
	if(vis[x] == 2) {
		return 1;
	}
	vis[x]=2; // active
	for(auto v:V[x]){ 
		if(vis[v] == 2) return 1;
		if(vis[v] == 1) continue;
		else chmax(res, dfs(v));
	}
	vis[x]=1;
	return res;
}
void solve(){
	int n; cin >> n;
	FOR(i,1,n-1) {
		int a,b; cin >> a >> b;
		adj[a].pb(b);
		adj[b].pb(a);
	}
	dfs(1,-1,0);
	int m; cin >> m;
	FOR(i,1,m) cin >> S[i] >> T[i];
	bool bad=0;
	FOR(i,1,m){
		FOR(j,1,m){
			if(i!=j) {
				// check if there's an edge between i and j
				bool y1=onpath(S[i],T[i],S[j]);
				bool y2=onpath(S[i],T[i],T[j]);
				db2(i,j);
				db2(y1,y2);
				if(y1&&y2){
					reach
					bad=1;
					goto done;
				}
				if(y1) { // you must do j before i
					V[j].insert(i);
				} 
				if(y2) { // you must do j after i
					V[i].insert(j);
				}
			}
		}
	}
	FOR(i,1,m) {
		dbv(V[i]);
	}
	
	FOR(i,1,m) {
		if(!vis[i])chmax(bad, dfs(i));
		db(i);
		db(bad);
	}
	done:;
	if(bad)cout<<"NO\n";
	else cout<<"YES\n";

	cnt=0;
	FOR(i,1,n)FOR(j,0,19)twok[i][j]=-1;
	FOR(i,1,n)pre[i]=post[i]=0;
	FOR(i,1,n)dep[i]=0;
	FOR(i,1,m)vis[i]=0;
	FOR(i,1,m)V[i].clear();
	FOR(i,1,n)S[i]=T[i]=0;
	FOR(i,1,n)adj[i].clear();
}
int32_t main() 
{
	IAMSPEED
	cin >> q;
	while(q--)solve();

}

Subtask #1
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #2
0 / 5.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #3
0 / 16.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #4
0 / 28.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #5
0 / 12.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #6
0 / 11.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8752 KB Output isn't correct
2 Halted 0 ms 0 KB -

Subtask #7
0 / 23.0

# 결과 실행 시간 메모리 Grader output
1 Incorrect 4 ms 8788 KB Output isn't correct
2 Halted 0 ms 0 KB -