답안 #725268

# 제출 시각 아이디 문제 언어 결과 실행 시간 메모리
725268 2023-04-17T06:01:30 Z acatmeowmeow Osmosmjerka (COCI17_osmosmjerka) C++11
100 / 160
4000 ms 10736 KB
#include <bits/stdc++.h>

using namespace std;

#define int long long 

int gcd(int a, int b) {
	return !b ? a : gcd(b, a % b);
}

signed main() {
	ios::sync_with_stdio(false);
	cin.tie(nullptr);
	int n, m, l;
	cin >> n >> m >> l;
	vector<vector<char>> grid(n + 5, vector<char>(m + 5));
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			cin >> grid[i][j];
		}
	}
	vector<int> dx = {-1, -1, 0, 1, 1, 1, 0, -1}, dy = {0, 1, 1, 1, 0, -1, -1, -1};
	map<tuple<int, int, int, int>, int> cnt;
	int sz = min(l, max(n, m)), r = l % sz, total = 0;
	const int base1 = 31, base2 = 53, modulo1 = 1e9 + 7, modulo2 = 1e9 + 9;
	for (int i = 0; i < n; i++) {
		for (int j = 0; j < m; j++) {
			for (int d = 0; d < 8; d++) {
				int hsh1 = 0, rhsh1 = 0, hsh2 = 0, rhsh2 = 0;
				for (int k = 0; k < sz; k++) {
					int curx = (i + (k*dx[d]) % n + n) % n, cury = (j + (k*dy[d]) % m + m) % m;
					hsh1 = (hsh1*base1) % modulo1 + (grid[curx][cury] - 'a' + 1), hsh1 %= modulo1;
					hsh2 = (hsh2*base2) % modulo2 + (grid[curx][cury] - 'a' + 1), hsh2 %= modulo2;
					if (k >= r) continue;
					rhsh1 = (rhsh1*base1) % modulo1 + (grid[curx][cury] - 'a' + 1), rhsh1 %= modulo1;
					rhsh2 = (rhsh2*base2) % modulo2 + (grid[curx][cury] - 'a' + 1), rhsh2 %= modulo2;
				}
				cnt[tuple<int, int, int, int>(hsh1, rhsh1, hsh2, rhsh2)]++;
				total++;
			}
		}
	}
	int ans = 0;
	for (auto&x : cnt) ans += x.second*x.second;
	total *= total;
	int d = gcd(ans, total);
	ans /= d, total /= d;
	cout << ans << "/" << total << '\n';
	return 0;
}
# 결과 실행 시간 메모리 Grader output
1 Correct 0 ms 212 KB Output is correct
2 Correct 0 ms 212 KB Output is correct
3 Correct 1 ms 340 KB Output is correct
4 Correct 2 ms 340 KB Output is correct
5 Correct 12 ms 468 KB Output is correct
6 Incorrect 138 ms 2004 KB Output isn't correct
7 Incorrect 2915 ms 10736 KB Output isn't correct
8 Execution timed out 4054 ms 9604 KB Time limit exceeded