이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <iostream>
#include <vector>
using namespace std;
using ll = long long;
const int N = 1000;
const int K = 200;
int n, k;
ll a[N + 5], pfx_sum[N + 5];
pair<ll, int> dp[K + 5][N + 5];
ll score(int i, int j) {
return pfx_sum[i] * (pfx_sum[n] - pfx_sum[j]);
}
pair<ll, vector<int>> retrieve() {
ll x = 0;
vector<int> v = {-1};
for (int i = 1; i <= n; i++) {
if (dp[k][i].first > x) {
x = dp[k][i].first;
v.back() = i;
}
}
for (int i = k; i >= 2; i--) {
v.push_back(dp[i][v.back()].second);
}
return {x, v};
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
if (n > N) exit(0);
a[0] = pfx_sum[0] = 0;
for (int i = 1; i <= n; i++) {
cin >> a[i];
pfx_sum[i] = a[i] + pfx_sum[i - 1];
}
for (int i = 1; i <= n; i++) {
dp[1][i] = {score(i, i), -1};
for (int s = 2; s <= k; s++) {
dp[s][i] = {-1, -1};
for (int j = 1; j < i; j++) {
if (dp[s - 1][j].first == -1) continue;
dp[s][i] = max(dp[s][i], {score(i, i) - score(j, i) + dp[s - 1][j].first, j});
}
}
}
pair<ll, vector<int>> ans = retrieve();
cout << ans.first << '\n';
for (int i : ans.second) {
cout << i << ' ';
}
cout << '\n';
return 0;
}
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