이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include <bits/stdc++.h>
#define FAST ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);cerr.tie(0)
#define mp make_pair
#define xx first
#define yy second
#define pb push_back
#define pf push_front
#define popb pop_back
#define popf pop_front
#define all(x) x.begin(),x.end()
#define ff(i,a,b) for (int i = a; i < b; i++)
#define fff(i,a,b) for (int i = a; i <= b; i++)
#define bff(i,a,b) for (int i = b-1; i >= a; i--)
#define bfff(i,a,b) for (int i = b; i >= a; i--)
using namespace std;
long double typedef ld;
unsigned int typedef ui;
long long int typedef li;
pair<int,int> typedef pii;
pair<li,li> typedef pli;
pair<ld,ld> typedef pld;
vector<vector<int>> typedef graph;
unsigned long long int typedef ull;
//const int mod = 998244353;
const int mod = 1000000007;
//Note to self: Check for overflow
set<pair<int,pii>> prim;
pair<int,pii> ed[100003];
pair<int,pii> qry[100003];
int up[50003];
int Up(int x)
{
if (up[x]<0) return x;
return up[x]=Up(up[x]);
}
void dsu(int a, int b)
{
a=Up(a),b=Up(b); if (a==b) return;
if (up[a]<up[b]) swap(a,b);
up[b]+=up[a],up[a]=b;
}
void rebuild(int n)
{
fff(i,1,n) up[i]=-1;
}
void solvebrut(int n, int m, int q)
{
fff(i,1,q)
{
if (qry[i].xx==1)
{
ed[qry[i].yy.xx].xx=qry[i].yy.yy;
}
else
{
rebuild(n);
fff(j,1,m) if (ed[j].xx>=qry[i].yy.yy) dsu(ed[j].yy.xx,ed[j].yy.yy);
cout<<-up[Up(qry[i].yy.xx)]<<"\n";
}
}
}
int ans[100005];
void solvenoupdates(int n, int m, int q)
{
rebuild(n);
vector<pair<pii,int>> offline;
fff(i,1,q) offline.pb({qry[i].yy,i});
sort(all(offline));
/*while (!prim.empty())
{
while (!offline.empty() && offline.back().xx.xx>(*prev(prim.end())).xx)
{
ans[offline.back().yy]=-up[offline.back().xx.yy];
offline.popb();
}
dsu((*prev(prim.end())).yy.xx,(*prev(prim.end())).yy.yy);
prim.erase(prev(prim.end()));
}*/
while (!offline.empty())
{
ans[offline.back().yy]=-up[offline.back().xx.yy];
offline.popb();
}
fff(i,1,q) cout<<ans[i]<<"\n";
}
int main()
{
FAST;
int n,m; cin>>n>>m;
fff(i,1,m)
{
cin>>ed[i].yy.xx>>ed[i].yy.yy>>ed[i].xx;
prim.insert(ed[i]);
}
int q; cin>>q;
fff(i,1,q) cin>>qry[i].xx>>qry[i].yy.xx>>qry[i].yy.yy;
if (n<=1000 && m<=1000 && q<=10000) solvebrut(n,m,q);
else solvenoupdates(n,m,q);
}
//Note to self: Check for overflow
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