이 제출은 이전 버전의 oj.uz에서 채점하였습니다. 현재는 제출 당시와는 다른 서버에서 채점을 하기 때문에, 다시 제출하면 결과가 달라질 수도 있습니다.
#include<bits/stdc++.h>
using namespace std;
using ll = long long;
struct dsu {
vector<int> par;
vector<ll> sum;
vector<vector<int>> el;
vector<set<int>> ed;
dsu(int n, vector<int> s) : par(n), sum(s.begin(), s.end()), el(n), ed(n) {
for (int i = 0; i < n; i++) par[i] = i, el[i] = {i};
}
int get(int i) {
return par[i] == i ? par[i] : par[i] = get(par[i]);
}
void edge(int i, int j) {
ed[get(i)].insert(j);
}
void merge(int a, int b) {
a = get(a);
b = get(b);
if (el[a].size() < el[b].size())
swap(a, b);
if (a != b) {
par[b] =a;
sum[a] += sum[b];
for (int x : el[b])
el[a].push_back(x);
if (ed[a].size() < ed[b].size())
swap(ed[a], ed[b]);
for (int x : ed[b])
ed[a].insert(x);
}
}
};
int main() {
int n, m;
cin >> n >> m;
vector s(n, 0);
for (int& i : s) cin >> i;
vector<int> ix(n);
for (int i{}; i < n ;i++) ix[i] = i;
stable_sort(ix.begin(), ix.end(), [&](int a, int b) {
return s[a] > s[b];
});
vector<int> jx(n);
for (int i = 0; i < n; i ++)
jx[ix[i]] = i;
stable_sort(s.begin(), s.end(), greater{});
vector<vector<int>> adj(n);
for (int i = 0; i < m ;i++) {
int u, v;
cin >> u >> v;
u--;v--;
adj[jx[u]].push_back(jx[v]);
adj[jx[v]].push_back(jx[u]);
}
for (int i = 0; i < n; i++) {
sort(adj[i].begin(), adj[i].end());
}
//for (int i : ix) cout << i << ' ';cout << endl;
//for (int i : jx) cout << i << ' ';cout << endl;
//for (int i : s) cout << i << ' ';cout << endl;
string res(n, '?');
vector<int> back(n, -1);
dsu cc(n, s);
for (int i =n -1; i >= 0;i --) {
for (int j : adj[i]) {
cc.edge(i, j);
if (j > i)
cc.merge(i, j);
}
int c = cc.get(i);
ll sum = cc.sum[c];
auto it = cc.ed[c].lower_bound(i);
if (it != cc.ed[c].begin()) {
--it;
back[i] = max(back[i], *it);
}
if (back[i] != -1 && s[back[i]] > sum)
back[i] = -1;
if (back[i] == -1) {
if (i == 0)
res[i] = '1';
else res[i] = '0';
}
}
string ans(n, '?');
for (int i = 1; i < n;i++) {
if (back[i] != -1) res[i] = res[back[i]];
}
for (int i = 0; i < n; i++) {
ans[ix[i]] = res[i];
}
cout << ans << '\n';
}
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